A community for students.
Here's the question you clicked on:
 0 viewing
4meisu
 2 years ago
t = 2π √l/g Rearrange to make g the subject.
4meisu
 2 years ago
t = 2π √l/g Rearrange to make g the subject.

This Question is Closed

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large t=2\pi \frac{\sqrt \ell}{g}\]Is that formatted correctly? With the way it's written, it's a little hard to tell whether or not you have the g placed in the square root.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2If this is correct, here are the steps we would take: ~Multiply both sides by g,\[\large g t=2\pi \frac{\sqrt \ell}{\cancel g}\cancel g\]The g's will cancel out on the right, ~Divide both sides by t,\[\large \frac{g \cancel t}{\cancel t}=2\pi \frac{\sqrt \ell}{t}\]The t's will cancel on the left, giving us,\[\large \color{brown}{g=2\pi \frac{\sqrt \ell}{t}}\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.2Alternatively, if you meant to write,\[\large t=2\pi \sqrt{\frac{\ell}{g}}\]We would start by writing it like this,\[\large t=2\pi \dfrac{\sqrt \ell}{\sqrt g}\]Then we would apply similar steps to the last method, ~Multiply both sides by \(\sqrt g\), \[\large t \sqrt g=2\pi \frac{\sqrt \ell}{\cancel{\sqrt g}}\cancel{\sqrt g} \qquad \rightarrow \qquad t \sqrt g=2\pi \sqrt \ell\]~Then divide both sides by t, \[\large \frac{\cancel t \sqrt g}{\cancel t}=2\pi\frac{\sqrt \ell}{t} \qquad \rightarrow \qquad \sqrt g=2\pi \frac{\sqrt \ell}{t}\] ~Then we'll finish up by squaring both sides,\[\large \left(\sqrt g\right)^2=\left(2\pi \frac{\sqrt \ell}{t}\right)^2 \qquad \rightarrow \qquad g=2^2 \pi^2\frac{(\sqrt \ell)^2}{t^2}\]When we square a term, we square `every part of it` as I have done above. Which gives us,\[\large \color{brown}{g=4\pi^2\frac{\ell}{t^2}}\]

4meisu
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you, that was very helpful and easy to understand :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.