A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
No idea how to solve this..
The halflife of radium is 1690 years. If 10 grams is present now, how much will be present in 50 years?
 one year ago
No idea how to solve this.. The halflife of radium is 1690 years. If 10 grams is present now, how much will be present in 50 years?

This Question is Closed

matricked
 one year ago
Best ResponseYou've already chosen the best response.0here first of all find the disintegrating constant

matricked
 one year ago
Best ResponseYou've already chosen the best response.0i am not sure abt the formula but it is somewhat like disintegrating constant =0.693/(hallife time)

matricked
 one year ago
Best ResponseYou've already chosen the best response.0then use ln (amt present after t yrs/amt initially present) = (disintegrating constant)* time

toadytica305
 one year ago
Best ResponseYou've already chosen the best response.0@Kira_Yamato Can you explain how you did it?

dpaInc
 one year ago
Best ResponseYou've already chosen the best response.1radio active decay problems modelled by : \(\large y=Ce^{kt} \) where C is your initial amount (10 grams), and k is your "disintegrating" constant as explained by @matricked. you'll need to find k so you'll need to solve the equation: \(\large 5=10e^{k \cdot 1690} \) because the halflife is 1690 years, there will only be 5 grams left of the original 10 grams when 1690 years have elapsed. This is what @Kira Yamato did above. k=(ln2)/1690. So the model for the halflife decay is: \(\large y=10e^{(\frac{ln2}{1690}\cdot t)} \) To answer your question, use a calculator to find y when t=50 years.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.