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toadytica305
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No idea how to solve this..
The halflife of radium is 1690 years. If 10 grams is present now, how much will be present in 50 years?
 one year ago
 one year ago
toadytica305 Group Title
No idea how to solve this.. The halflife of radium is 1690 years. If 10 grams is present now, how much will be present in 50 years?
 one year ago
 one year ago

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matricked Group TitleBest ResponseYou've already chosen the best response.0
here first of all find the disintegrating constant
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
i am not sure abt the formula but it is somewhat like disintegrating constant =0.693/(hallife time)
 one year ago

matricked Group TitleBest ResponseYou've already chosen the best response.0
then use ln (amt present after t yrs/amt initially present) = (disintegrating constant)* time
 one year ago

toadytica305 Group TitleBest ResponseYou've already chosen the best response.0
@Kira_Yamato Can you explain how you did it?
 one year ago

dpaInc Group TitleBest ResponseYou've already chosen the best response.1
radio active decay problems modelled by : \(\large y=Ce^{kt} \) where C is your initial amount (10 grams), and k is your "disintegrating" constant as explained by @matricked. you'll need to find k so you'll need to solve the equation: \(\large 5=10e^{k \cdot 1690} \) because the halflife is 1690 years, there will only be 5 grams left of the original 10 grams when 1690 years have elapsed. This is what @Kira Yamato did above. k=(ln2)/1690. So the model for the halflife decay is: \(\large y=10e^{(\frac{ln2}{1690}\cdot t)} \) To answer your question, use a calculator to find y when t=50 years.
 one year ago
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