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can any one show me steps how to do this so i can see where i went wrong i keep getting 0.6918
2835.48= 2310.72(1+r/2)^10 1.2271 = (1+r/2)^10 1.02067 = 1+ r/2 .02067 = r/2 r = 0.04135 => 4.1%

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Other answers:

Roberta deposited $4,790.23 into a savings account with an interest rate of 3.8% compounded twice a year. About how long will it take for the account to be worth $9,000? A = P(1+r/n)^(nt) 9000 = 4790.23(1+0.038/2)^(2t) solve for t
but i don't understand the logitude part? the in idk how to do it
i'll do what i can and stop where i don't undersstand okay hold on
9000 = 4790.23(1+0.038/2)^(2t) 9000=4790.23(1+0.038/2)^2t ----- -------- 1.8788=1.019^2t 1.8788=1.0383t t=1.8094??
no it's much more than 1.8 years
i know next i have to do a proportion that idk how to do
A=P(1+r/n)^(n*t) 9000=4790.23(1+0.038/2)^(2*t) 9000=4790.23(1+0.019)^(2*t) 9000=4790.23(1.019)^(2*t) 9000/4790.23 = (1.019)^(2*t) (1.019)^(2*t) = 9000/4790.23 (1.019)^(2*t) = 1.87882 log( (1.019)^(2*t) ) = log( 1.87882 ) 2t*log( 1.019 ) = log( 1.87882 ) 2t = log( 1.87882 )/log( 1.019 ) 2t = 33.506118 t = 33.506118/2 t = 16.753059 t = 16.75 t = 16+0.75 years t = 16 years + 0.75 years t = 16 years + 0.75*12 months t = 16 years + 9 months t = 16 years, 9 months
The key to solving for t, which is in the exponent, is to use logs to isolate it
A=P(1+r/n)^(n*t) A=7775(1+0.045/n)^(n*14) Now plug in n = 365. If you get 14,398.87 for A, or close enough to it, then the answer is "daily". If not, then move onto n = 12, n = 4, and n = 1 until you find your answer.
for 365 i got 12960.26204
you should have gotten A = 14597.86 when n = 365
try it again I recommend using a graphing calculator and using the table if you can
ohh i got it its 14597.85537
so its daily
yep, it's daily
oh i get it 365=daily 12=monthly 1-yearly quartly=4 right?
yep n = 365 means you compound 365 days a year (assuming not a leap year)
ie you compound 365 times a year
n = 4 means you compound 4 times a year, etc etc
it wasn't daily check what went wrong

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