## anonymous 3 years ago I just want to clear up something to do with factorising indices. Can someone just spend a little time for me :)

1. anonymous

Which term would you factor out? Because you can take out 2^2n or 2^n-1. Which one should you take out? Or its just random $\huge\frac{2^{2n}-2^{n-1} }{ 2^{n}-2^{-1} }$

2. anonymous

for the numerator it would be $\huge2^{2n}(1 - 2^{-n-1})$ Would it?

3. anonymous

What if you factor out just $$2^n$$

4. anonymous

well ill try |dw:1359854348941:dw| this is right?

5. anonymous

|dw:1359854381094:dw|

6. anonymous

$\huge\frac{2^{2n}-2^{n-1} }{ 2^{n}-2^{-1} }$ $\huge\frac{2^n(2^{n}-2^{-1} )}{ 2^{n}-2^{-1} }$

7. anonymous

oh yes thats right :)

8. anonymous

so how did you know to factor out 2^n? You just looked at it?

9. anonymous

I wanted something similar to the bottom.

10. anonymous

so you keep thinking of a number to factor out till you can simplify?

11. Kuoministers

you should be able to think a good number to factor out when you have experience :)