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anonymous
 3 years ago
I just want to clear up something to do with factorising indices. Can someone just spend a little time for me :)
anonymous
 3 years ago
I just want to clear up something to do with factorising indices. Can someone just spend a little time for me :)

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which term would you factor out? Because you can take out 2^2n or 2^n1. Which one should you take out? Or its just random \[\huge\frac{2^{2n}2^{n1} }{ 2^{n}2^{1} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for the numerator it would be \[\huge2^{2n}(1  2^{n1})\] Would it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What if you factor out just \(2^n\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well ill try dw:1359854348941:dw this is right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359854381094:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \huge\frac{2^{2n}2^{n1} }{ 2^{n}2^{1} } \] \[ \huge\frac{2^n(2^{n}2^{1} )}{ 2^{n}2^{1} } \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh yes thats right :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how did you know to factor out 2^n? You just looked at it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I wanted something similar to the bottom.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so you keep thinking of a number to factor out till you can simplify?

Kuoministers
 3 years ago
Best ResponseYou've already chosen the best response.0you should be able to think a good number to factor out when you have experience :)
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