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TeemoTheTerific

  • one year ago

I just want to clear up something to do with factorising indices. Can someone just spend a little time for me :)

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  1. TeemoTheTerific
    • one year ago
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    Which term would you factor out? Because you can take out 2^2n or 2^n-1. Which one should you take out? Or its just random \[\huge\frac{2^{2n}-2^{n-1} }{ 2^{n}-2^{-1} }\]

  2. TeemoTheTerific
    • one year ago
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    for the numerator it would be \[\huge2^{2n}(1 - 2^{-n-1})\] Would it?

  3. wio
    • one year ago
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    What if you factor out just \(2^n\)

  4. TeemoTheTerific
    • one year ago
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    well ill try |dw:1359854348941:dw| this is right?

  5. TeemoTheTerific
    • one year ago
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    |dw:1359854381094:dw|

  6. wio
    • one year ago
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    \[ \huge\frac{2^{2n}-2^{n-1} }{ 2^{n}-2^{-1} } \] \[ \huge\frac{2^n(2^{n}-2^{-1} )}{ 2^{n}-2^{-1} } \]

  7. TeemoTheTerific
    • one year ago
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    oh yes thats right :)

  8. TeemoTheTerific
    • one year ago
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    so how did you know to factor out 2^n? You just looked at it?

  9. wio
    • one year ago
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    I wanted something similar to the bottom.

  10. TeemoTheTerific
    • one year ago
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    so you keep thinking of a number to factor out till you can simplify?

  11. Kuoministers
    • one year ago
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    you should be able to think a good number to factor out when you have experience :)

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