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daustin15
 3 years ago
AC + BC could equal 15
Always
Never
Sometimes
daustin15
 3 years ago
AC + BC could equal 15 Always Never Sometimes

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UsukiDoll
 3 years ago
Best ResponseYou've already chosen the best response.0Well one side is 9. This can get tricky since if A = 1, B = 1, and C = 9 you'll have 18. And you can't have a zero side or a negative side. That's impossible

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1\[\rm AC = 9\]Now apply the Pythagorean Theorem.\[9^2 + x^2 = 15^2\]Any solutions to the above?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1Turns out they could never, because the only solution is \(12\) but \(9 + 12 = 21\)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1Also thinking about how AC + BC > 15, we could never get AC + BC = 15.

UsukiDoll
 3 years ago
Best ResponseYou've already chosen the best response.0oh I remember doing that PArth...

Directrix
 3 years ago
Best ResponseYou've already chosen the best response.0Triangle Inequality Theorem: One side of a triangle is less than the sum of the other two. Therefore, 15 < AC + BC which is equivalent to AC + BC > 15. AC + BC could never be equal to 15. There would be no triangle. @daustin15
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