anonymous
  • anonymous
AC + BC could equal 15 Always Never Sometimes
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
UsukiDoll
  • UsukiDoll
Well one side is 9. This can get tricky since if A = 1, B = 1, and C = 9 you'll have 18. And you can't have a zero side or a negative side. That's impossible
ParthKohli
  • ParthKohli
\[\rm AC = 9\]Now apply the Pythagorean Theorem.\[9^2 + x^2 = 15^2\]Any solutions to the above?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ParthKohli
  • ParthKohli
Turns out they could never, because the only solution is \(12\) but \(9 + 12 = 21\)
ParthKohli
  • ParthKohli
Also thinking about how AC + BC > 15, we could never get AC + BC = 15.
UsukiDoll
  • UsukiDoll
oh I remember doing that PArth...
ParthKohli
  • ParthKohli
Erm?
UsukiDoll
  • UsukiDoll
the a^2+b^2 = c^2
Directrix
  • Directrix
Triangle Inequality Theorem: One side of a triangle is less than the sum of the other two. Therefore, 15 < AC + BC which is equivalent to AC + BC > 15. AC + BC could never be equal to 15. There would be no triangle. @daustin15

Looking for something else?

Not the answer you are looking for? Search for more explanations.