daustin15 Group Title AC + BC could equal 15 Always Never Sometimes one year ago one year ago

1. daustin15 Group Title

2. UsukiDoll Group Title

Well one side is 9. This can get tricky since if A = 1, B = 1, and C = 9 you'll have 18. And you can't have a zero side or a negative side. That's impossible

3. ParthKohli Group Title

$\rm AC = 9$Now apply the Pythagorean Theorem.$9^2 + x^2 = 15^2$Any solutions to the above?

4. ParthKohli Group Title

Turns out they could never, because the only solution is $$12$$ but $$9 + 12 = 21$$

5. ParthKohli Group Title

Also thinking about how AC + BC > 15, we could never get AC + BC = 15.

6. UsukiDoll Group Title

oh I remember doing that PArth...

7. ParthKohli Group Title

Erm?

8. UsukiDoll Group Title

the a^2+b^2 = c^2

9. Directrix Group Title

Triangle Inequality Theorem: One side of a triangle is less than the sum of the other two. Therefore, 15 < AC + BC which is equivalent to AC + BC > 15. AC + BC could never be equal to 15. There would be no triangle. @daustin15