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\[\rm AC = 9\]Now apply the Pythagorean Theorem.\[9^2 + x^2 = 15^2\]Any solutions to the above?

Turns out they could never, because the only solution is \(12\) but \(9 + 12 = 21\)

Also thinking about how AC + BC > 15, we could never get AC + BC = 15.

oh I remember doing that PArth...

Erm?

the a^2+b^2 = c^2