Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Find an exact value. cos 15°

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
setting 15 = (45-30)
then use the formula : cos(A-B) = cosAcosB + sinAsinB

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

here given A=45 and B=30 degrees
cos 45cos30 +sin45cos30?
45 and 30 are the special angles.. u have to remember the values of sin and cos for angles 30 and 45 degrees
ok. how do i solve from here?
u just put the values of them (sin45, sin 30, cos45, cos 30)
cos 45cos30 +sin45cos30 = ... (calculate it and simply)
i got this
hmm.. what identity did u use ? it should be : cos 45cos30 +sin45cos30 do u know the exactly value of sin30 ? sin45 ? cos30 ? cos45 ?
just put the values cos45 =1/root 2 and cos 30= root3/2
sin 45=1/root ovr2 and sin 30=1/2...the multiply and add
1/root ovr2 or 1/ root 2?
its the same thing...
o

Not the answer you are looking for?

Search for more explanations.

Ask your own question