## azolotor Group Title I know others may have asked this but I just don't understand it as hard as I have tried. I have gone through the solution and it still isn't gelling An ideal (non-viscous) liquid with a density of ! is poured into a cylindrical vessel with a cross-sectional area of A1 to a level at a height h from the bottom. The bottom has an opening with a cross-sectional area A2 . Find the time it takes the k=liquid to flow out. I don't understand what b is or necessarily why v=0 x=-1/2. Thanks in advance one year ago one year ago

v=0 relative to the liquid flowing at the bottom. !!Processing error!! There is no specified b or x in your question.

2. azolotor Group Title

I don't understand what you mean v=0 relative to the liquid flowing at the bottom. and let me recopy the question my apologies. An ideal (non-viscous) liquid with a density of rho is poured into a cylindrical vessel with a cross-sectional area of A1 to a level at a height h from the bottom. The bottom has an opening with a cross-sectional area A2. Find the time it takes the k=liquid to flow out

according to the continuity of the liquid, $$A_1v_1=A_2v_2$$ v_1 is the velocity of the fluid in A_1 and v_2 is the velocity of the fluid at A_2 section. $$v_1=\frac{A_2}{A_1}v_2$$ Normally in these kind of problems the hole at the bottom is very smaller than the cross sectional area at the higher level thus makes A_2/A_1 is considerably small. So with respect to v_2, v_1 is negligible. So we take v_1=0

4. azolotor Group Title

What do you mean by the continuity of the liquid?