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HPlourde
 2 years ago
what is (cosx/sinx)/sinxcosx simplified
HPlourde
 2 years ago
what is (cosx/sinx)/sinxcosx simplified

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abb0t
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ \cos(x) }{ \sin(x) } \times \frac{ \sin(x)\cos(x) }{ 1 }\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x}\]Woops I dunno if you're looking at it correctly abbot :O Only the top one is a fraction.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x} \qquad = \qquad \left(\frac{\cos x}{\sin x}\right)\frac{1}{\sin x \cos x}\]

HPlourde
 2 years ago
Best ResponseYou've already chosen the best response.0ya but what about multiplying by the recipricol.... cause i am seriously confused.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large \left(\frac{\cancel{\cos x}}{\sin x}\right)\frac{1}{\sin x \cancel{\cos x}}\]

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0Ok here's the thing with the reciprocal :) lemme explain.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0The bottom fraction is actually this,\[\large \frac{\sin x \cos x}{1}\] So if you wanted to write it as a division of fractions, you could write it like this,\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x} \qquad = \qquad \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\left(\dfrac{\sin x \cos x}{1}\right)}\]And then from here, we could multiply by the reciprocal of the bottom fraction.

HPlourde
 2 years ago
Best ResponseYou've already chosen the best response.0aha!!!!! now it's making sense!!!

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.0When we started this problem, we weren't dividing fractions. Only the top one was a fraction. Maybe that's why there was a little confusion :)

HPlourde
 2 years ago
Best ResponseYou've already chosen the best response.0i think so...this is the only one that i've been confused over so far... thank you:)

HPlourde
 2 years ago
Best ResponseYou've already chosen the best response.0i got the right answer. thanks a billion
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