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abb0t Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ \cos(x) }{ \sin(x) } \times \frac{ \sin(x)\cos(x) }{ 1 }\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x}\]Woops I dunno if you're looking at it correctly abbot :O Only the top one is a fraction.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x} \qquad = \qquad \left(\frac{\cos x}{\sin x}\right)\frac{1}{\sin x \cos x}\]
 one year ago

HPlourde Group TitleBest ResponseYou've already chosen the best response.0
ya but what about multiplying by the recipricol.... cause i am seriously confused.
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
\[\large \left(\frac{\cancel{\cos x}}{\sin x}\right)\frac{1}{\sin x \cancel{\cos x}}\]
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Ok here's the thing with the reciprocal :) lemme explain.
 one year ago

HPlourde Group TitleBest ResponseYou've already chosen the best response.0
ok sounds good
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
The bottom fraction is actually this,\[\large \frac{\sin x \cos x}{1}\] So if you wanted to write it as a division of fractions, you could write it like this,\[\large \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\sin x \cos x} \qquad = \qquad \frac{\left(\dfrac{\cos x}{\sin x}\right)}{\left(\dfrac{\sin x \cos x}{1}\right)}\]And then from here, we could multiply by the reciprocal of the bottom fraction.
 one year ago

HPlourde Group TitleBest ResponseYou've already chosen the best response.0
aha!!!!! now it's making sense!!!
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
When we started this problem, we weren't dividing fractions. Only the top one was a fraction. Maybe that's why there was a little confusion :)
 one year ago

HPlourde Group TitleBest ResponseYou've already chosen the best response.0
i think so...this is the only one that i've been confused over so far... thank you:)
 one year ago

HPlourde Group TitleBest ResponseYou've already chosen the best response.0
i got the right answer. thanks a billion
 one year ago
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