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mathlilly

  • 3 years ago

why does x^2+y^2 = 4-c have no real solutions? (book example about functions of several variables and graphing functions)

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  1. tom_math
    • 3 years ago
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    \[\forall c \le 4, x^{2}+y ^{2} = 4 - c, is the equation for a circle with radius = \sqrt{4-c}\]

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