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TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359872594130:dw

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0i know formula a^2  2ab + b^2

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0i dont get it :P

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359872887253:dwbtw original question is

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0thats original quesiton

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0yes your right now hartnn :)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1can you simplify that now ?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0is there a way to do this question using indices laws?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0cause my teacher prefers that :P

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i have used law od indices \(2^{1/2}.2^{1/2}= 2^{1/2+1/2}=2^1=2\)

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.0yes thank you so much

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1\[(2^{1/2}  2^{1/2})^2 = (2^{1/2}2^{1/2})(2^{1/2}2^{1/2})=\]\[2^{1/2}*2^{1/2}2^{1/2}2^{1/2}  2^{1/2}2^{1/2} + 2^{1/2}2^{1/2} = \]\[2^12^02^0+2^{1} = 2  1  1 + \frac{1}{2} = \frac{1}{2}\]

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.1Maybe easier to write \(a = 2^{1/2}\) and \(b = a^{1/2}\) then \[(ab)^2 = a^2  2ab + b^2 = (2^{1/2})^{1/2}  2*2^{1/2}*2^{1/2} + (2^{1/2})^2 =\]\[2^1  2*2^0 + 2^{1} = 2^{1} = \frac{1}{2}\] and use some different properties :)
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