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TeemoTheTerific
Group Title
Simplify
(2^1/2  2^1/2)^2
ill write it neater. Please help
 one year ago
 one year ago
TeemoTheTerific Group Title
Simplify (2^1/2  2^1/2)^2 ill write it neater. Please help
 one year ago
 one year ago

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TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
dw:1359872594130:dw
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
i know formula a^2  2ab + b^2
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
i dont get it :P
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
dw:1359872887253:dwbtw original question is
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
thats original quesiton
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359872899922:dw
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
yes your right now hartnn :)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359872998532:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
can you simplify that now ?
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
answer 5?
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
is there a way to do this question using indices laws?
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
cause my teacher prefers that :P
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, 5 is correct.
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i have used law od indices \(2^{1/2}.2^{1/2}= 2^{1/2+1/2}=2^1=2\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359873234483:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359873310197:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
got that^ ?
 one year ago

TeemoTheTerific Group TitleBest ResponseYou've already chosen the best response.0
yes thank you so much
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
welcome ^_^
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[(2^{1/2}  2^{1/2})^2 = (2^{1/2}2^{1/2})(2^{1/2}2^{1/2})=\]\[2^{1/2}*2^{1/2}2^{1/2}2^{1/2}  2^{1/2}2^{1/2} + 2^{1/2}2^{1/2} = \]\[2^12^02^0+2^{1} = 2  1  1 + \frac{1}{2} = \frac{1}{2}\]
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
Maybe easier to write \(a = 2^{1/2}\) and \(b = a^{1/2}\) then \[(ab)^2 = a^2  2ab + b^2 = (2^{1/2})^{1/2}  2*2^{1/2}*2^{1/2} + (2^{1/2})^2 =\]\[2^1  2*2^0 + 2^{1} = 2^{1} = \frac{1}{2}\] and use some different properties :)
 one year ago
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