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 one year ago
hi. a firstorder reaction has a half life of 26.4 seconds. how long will it take for the concentration of the reactant in the reaction to fall to 1/8 of its initial value? please help me omg
 one year ago
hi. a firstorder reaction has a half life of 26.4 seconds. how long will it take for the concentration of the reactant in the reaction to fall to 1/8 of its initial value? please help me omg

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miley28
 one year ago
Best ResponseYou've already chosen the best response.0i'll give u an easy formula for this.. time taken for conc. of reactant to fall is, n*half life=initial conc/\[2^{n}\]

miley28
 one year ago
Best ResponseYou've already chosen the best response.0since here it is given 1/8 of its initial value so accordin to the formula, 3*26.4=initial conc/\[2^{3}\] thus time taken is=3*26.4=79.2secs

miley28
 one year ago
Best ResponseYou've already chosen the best response.0but remember this formula is only applicable for 1st order reactions... or elase u may apply the general rate constant formulas.

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1first order reaction so use: \[t _{1/2}=\frac{ \ln2 }{ k }\] find k then, use: \[A=A _{0}e ^{kt}\] assume Ao= initial = 1 then A = 1/8 solve for t, time, which will be in seconds

missylulu
 one year ago
Best ResponseYou've already chosen the best response.0what formula is A = Ao e^kt ??

aaronq
 one year ago
Best ResponseYou've already chosen the best response.1general equation for exponential decay or growth

missylulu
 one year ago
Best ResponseYou've already chosen the best response.0oh that's right gahh sorry LOL
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