anonymous
  • anonymous
An ideal gas is subjected to a cyclic process ABCD as depicted in the P-V diagram given. Which of the following curves represents the equivalent cyclic process?
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Where is the 'given' P-V diagram?
anonymous
  • anonymous
|dw:1359433955167:dw|
anonymous
  • anonymous
The P-V diagram

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
What's the question? cyclic process equivalent to? any equation given?
anonymous
  • anonymous
The diagram is on the extreme left is the PV Diagram and the all the 4 options given on P-T diagram. My fault , I do not know how to amend the sketch as there is no eraser facility..One of the 4 options is right.
anonymous
  • anonymous
|dw:1359435181308:dw|
anonymous
  • anonymous
ok lets do this section by section.. in your original graph.. section A to B.. what kind of process is it??
anonymous
  • anonymous
It is const pr i.e isobaric one.
anonymous
  • anonymous
ok.. so you see that volume is expanding keeping pressure constant... now tell me during this process what happens to temperature?
anonymous
  • anonymous
PV=nRT v is directly proportional to T hence it creases.
anonymous
  • anonymous
correct.. so now.. match the options.. for AB section!!
anonymous
  • anonymous
which options can you eliminate ??
anonymous
  • anonymous
right extreme which is no 2 in this question.
anonymous
  • anonymous
|dw:1359878043806:dw| NOW TELL WHICH OPTION can you eliminate?
anonymous
  • anonymous
first column second row as it shows pr not constant. and as i have said right top most as the arrow is shown from B to A.( though I am not sure of that)
anonymous
  • anonymous
the arrow has to be opposite.. now i have marked 4 options dude.. i have called it A B C D.. :P.. so you are saying you can eliminate option C right??.. you are correct .. cause pressure is increasing in that you can also eliminate option A.. so its between option B and D..
anonymous
  • anonymous
why A? Pr as shown is constant here.
anonymous
  • anonymous
It was my fault not to show it correctly. Line a-b at A is parallel.
anonymous
  • anonymous
ohhww.. ok ok :).. fine.. so then lets continue with section BC.. what do you think happens?
anonymous
  • anonymous
It is either isothermal or adiabatic
anonymous
  • anonymous
yea well.. its very difficult to make out if its an isothermal or adiabatic!! :-/.. lets skip that.. and go to C-D process!!
anonymous
  • anonymous
It is ischoric , volume is const.
anonymous
  • anonymous
correct.. and pressure is decreasing.. so temperature should be decreasing.. time to eliminate one more option.. which one?
anonymous
  • anonymous
D
anonymous
  • anonymous
correct.. so now it boils down to whether the BC and DA processes are adiabatic or isothermal.. thats where i really dunno how to find out.. :-/.. but in your option B.. the order is opposite.. so if the directions are like that.. then option B can be eliminated right?
anonymous
  • anonymous
Problem is the correct option given is as B that is the right upper most. and not been explained. Pl help.
anonymous
  • anonymous
since its reversible maybe .. the direction doesn't matter.. !!!
anonymous
  • anonymous
you have to look at the curve in AB section.. if the curve is STEEEP .. its an adiabatic.. if the curve is not all that steep.. then its isothermal
anonymous
  • anonymous
can't draw :P.. http://physics.info/pressure-volume/ check this.. !!
anonymous
  • anonymous
Ok thanks I shall come back.
anonymous
  • anonymous
i need to go now.. sorry :(... but ll reply once i am back.. if no one else clears your doubt that is!!

Looking for something else?

Not the answer you are looking for? Search for more explanations.