## salparadise64 2 years ago question about break even point. I am not to sure how to tackle this, so any help would be greatly appreciated. "find the break even point of each pair of equation. round to nearest decimal answers to the nearest tenth." E=26 +3.2x I=4.5x im not sure what E and i stand for.

1. UnkleRhaukus

is there something in the question you haven't included?

ohhhhh im sorry it's E=26 + 3.2x sorry, sort of new here.

3. UnkleRhaukus

i think the break even point is where the lines cross

4. UnkleRhaukus

ie, the point that solves both the equations

so how would i go about this? should i just graph it in my calculator or is there some formula for this?

6. UnkleRhaukus

well i wold simply solve the second equation for x (by dividing by 4.5) and then substituting this into the first equation

so im looking for i?

8. UnkleRhaukus

your looking for the \(x\) that makes I=E

i got x= i/4.5 then plugged it into 26+ 3.2 (i/4.5) am i on the right path?

10. UnkleRhaukus

yeah, E=26+3.2 (i/4.5) simplify this a bit and you will have E in terms of I

okay, so im stuck at E= 26 +3.2i/4,5 i dont think i can those two values.

13. UnkleRhaukus

actually i think there is an better way to do this problem The break even point is when I=E so solve 26 +3.2x=4.5x

ohhh okay.

15. UnkleRhaukus

can you find \(x\) now?

Yes thank you, you are too awesome. i got x=20

17. UnkleRhaukus

good stuff, can you round that to the nearest tenth?

do i need to? it broke evenly.

19. UnkleRhaukus

im not sure,

i think the instructions might be in case it didnt break down evenly.

21. UnkleRhaukus

To be a point the point must have an \(x\) and a \(y\) value you've found \(x=20\) , to find \(y\) substitute \(x\) into either equation to get \(y\), then write the point like this \((x,y)\)

Y=i =4.5 * 20= 90 (20,90)?

23. UnkleRhaukus

Thats it \[(20,90)\checkmark\]