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anonymous
 3 years ago
question about break even point.
I am not to sure how to tackle this, so any help would be greatly appreciated.
"find the break even point of each pair of equation. round to nearest decimal answers to the nearest tenth."
E=26 +3.2x
I=4.5x
im not sure what E and i stand for.
anonymous
 3 years ago
question about break even point. I am not to sure how to tackle this, so any help would be greatly appreciated. "find the break even point of each pair of equation. round to nearest decimal answers to the nearest tenth." E=26 +3.2x I=4.5x im not sure what E and i stand for.

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UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2is there something in the question you haven't included?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ohhhhh im sorry it's E=26 + 3.2x sorry, sort of new here.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2i think the break even point is where the lines cross

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2ie, the point that solves both the equations

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so how would i go about this? should i just graph it in my calculator or is there some formula for this?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2well i wold simply solve the second equation for x (by dividing by 4.5) and then substituting this into the first equation

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2your looking for the \(x\) that makes I=E

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got x= i/4.5 then plugged it into 26+ 3.2 (i/4.5) am i on the right path?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2yeah, E=26+3.2 (i/4.5) simplify this a bit and you will have E in terms of I

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay, so im stuck at E= 26 +3.2i/4,5 i dont think i can those two values.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2actually i think there is an better way to do this problem The break even point is when I=E so solve 26 +3.2x=4.5x

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2can you find \(x\) now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes thank you, you are too awesome. i got x=20

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2good stuff, can you round that to the nearest tenth?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do i need to? it broke evenly.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think the instructions might be in case it didnt break down evenly.

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2To be a point the point must have an \(x\) and a \(y\) value you've found \(x=20\) , to find \(y\) substitute \(x\) into either equation to get \(y\), then write the point like this \((x,y)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Y=i =4.5 * 20= 90 (20,90)?

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.2Thats it \[(20,90)\checkmark\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0awesome, possum :) thanks for the help mate.
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