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salparadise64

question about break even point. I am not to sure how to tackle this, so any help would be greatly appreciated. "find the break even point of each pair of equation. round to nearest decimal answers to the nearest tenth." E=26 +3.2x I=4.5x im not sure what E and i stand for.

  • one year ago
  • one year ago

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  1. UnkleRhaukus
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    is there something in the question you haven't included?

    • one year ago
  2. salparadise64
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    ohhhhh im sorry it's E=26 + 3.2x sorry, sort of new here.

    • one year ago
  3. UnkleRhaukus
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    i think the break even point is where the lines cross

    • one year ago
  4. UnkleRhaukus
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    ie, the point that solves both the equations

    • one year ago
  5. salparadise64
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    so how would i go about this? should i just graph it in my calculator or is there some formula for this?

    • one year ago
  6. UnkleRhaukus
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    well i wold simply solve the second equation for x (by dividing by 4.5) and then substituting this into the first equation

    • one year ago
  7. salparadise64
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    so im looking for i?

    • one year ago
  8. UnkleRhaukus
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    your looking for the \(x\) that makes I=E

    • one year ago
  9. salparadise64
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    i got x= i/4.5 then plugged it into 26+ 3.2 (i/4.5) am i on the right path?

    • one year ago
  10. UnkleRhaukus
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    yeah, E=26+3.2 (i/4.5) simplify this a bit and you will have E in terms of I

    • one year ago
  11. salparadise64
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    okay, so im stuck at E= 26 +3.2i/4,5 i dont think i can those two values.

    • one year ago
  12. salparadise64
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    add those*

    • one year ago
  13. UnkleRhaukus
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    actually i think there is an better way to do this problem The break even point is when I=E so solve 26 +3.2x=4.5x

    • one year ago
  14. salparadise64
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    ohhh okay.

    • one year ago
  15. UnkleRhaukus
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    can you find \(x\) now?

    • one year ago
  16. salparadise64
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    Yes thank you, you are too awesome. i got x=20

    • one year ago
  17. UnkleRhaukus
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    good stuff, can you round that to the nearest tenth?

    • one year ago
  18. salparadise64
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    do i need to? it broke evenly.

    • one year ago
  19. UnkleRhaukus
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    im not sure,

    • one year ago
  20. salparadise64
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    i think the instructions might be in case it didnt break down evenly.

    • one year ago
  21. UnkleRhaukus
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    To be a point the point must have an \(x\) and a \(y\) value you've found \(x=20\) , to find \(y\) substitute \(x\) into either equation to get \(y\), then write the point like this \((x,y)\)

    • one year ago
  22. salparadise64
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    Y=i =4.5 * 20= 90 (20,90)?

    • one year ago
  23. UnkleRhaukus
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    Thats it \[(20,90)\checkmark\]

    • one year ago
  24. salparadise64
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    awesome, possum :) thanks for the help mate.

    • one year ago
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