anonymous
  • anonymous
question about break even point. I am not to sure how to tackle this, so any help would be greatly appreciated. "find the break even point of each pair of equation. round to nearest decimal answers to the nearest tenth." E=26 +3.2x I=4.5x im not sure what E and i stand for.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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UnkleRhaukus
  • UnkleRhaukus
is there something in the question you haven't included?
anonymous
  • anonymous
ohhhhh im sorry it's E=26 + 3.2x sorry, sort of new here.
UnkleRhaukus
  • UnkleRhaukus
i think the break even point is where the lines cross

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UnkleRhaukus
  • UnkleRhaukus
ie, the point that solves both the equations
anonymous
  • anonymous
so how would i go about this? should i just graph it in my calculator or is there some formula for this?
UnkleRhaukus
  • UnkleRhaukus
well i wold simply solve the second equation for x (by dividing by 4.5) and then substituting this into the first equation
anonymous
  • anonymous
so im looking for i?
UnkleRhaukus
  • UnkleRhaukus
your looking for the \(x\) that makes I=E
anonymous
  • anonymous
i got x= i/4.5 then plugged it into 26+ 3.2 (i/4.5) am i on the right path?
UnkleRhaukus
  • UnkleRhaukus
yeah, E=26+3.2 (i/4.5) simplify this a bit and you will have E in terms of I
anonymous
  • anonymous
okay, so im stuck at E= 26 +3.2i/4,5 i dont think i can those two values.
anonymous
  • anonymous
add those*
UnkleRhaukus
  • UnkleRhaukus
actually i think there is an better way to do this problem The break even point is when I=E so solve 26 +3.2x=4.5x
anonymous
  • anonymous
ohhh okay.
UnkleRhaukus
  • UnkleRhaukus
can you find \(x\) now?
anonymous
  • anonymous
Yes thank you, you are too awesome. i got x=20
UnkleRhaukus
  • UnkleRhaukus
good stuff, can you round that to the nearest tenth?
anonymous
  • anonymous
do i need to? it broke evenly.
UnkleRhaukus
  • UnkleRhaukus
im not sure,
anonymous
  • anonymous
i think the instructions might be in case it didnt break down evenly.
UnkleRhaukus
  • UnkleRhaukus
To be a point the point must have an \(x\) and a \(y\) value you've found \(x=20\) , to find \(y\) substitute \(x\) into either equation to get \(y\), then write the point like this \((x,y)\)
anonymous
  • anonymous
Y=i =4.5 * 20= 90 (20,90)?
UnkleRhaukus
  • UnkleRhaukus
Thats it \[(20,90)\checkmark\]
anonymous
  • anonymous
awesome, possum :) thanks for the help mate.

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