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Solmyr
Group Title
The three Math Idol judges have been eliminating contestants all day! The number of onestep equations and twostep equations who have been eliminated today is equal to 610! If four times the number of onestep equations minus twice the number of twostep equations is equal to 340, how many onestep equations auditioned today?
260
340
350
670
 one year ago
 one year ago
Solmyr Group Title
The three Math Idol judges have been eliminating contestants all day! The number of onestep equations and twostep equations who have been eliminated today is equal to 610! If four times the number of onestep equations minus twice the number of twostep equations is equal to 340, how many onestep equations auditioned today? 260 340 350 670
 one year ago
 one year ago

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azolotor Group TitleBest ResponseYou've already chosen the best response.1
\[610=x+y\]\[340=4x2y\] I created a system of equations out of the information they gave me. From there, solve for one variable and plug into the other. Make sense?
 one year ago

Solmyr Group TitleBest ResponseYou've already chosen the best response.0
actually i dont really understand it at all
 one year ago

azolotor Group TitleBest ResponseYou've already chosen the best response.1
Okay, so the first equation I wrote is the sum of all the one step and two step equations. They told us the sum of one step and two step equations is 610. For the second equation I again took the information they gave us. 4 times the amount of one step equations minus two times the number of two steps sums to 340. So x is the number of one step equations and y is number of two steps eqautions. That is where the two equations come from. To solve a two variable system of equations you need to isolate the variables in one of the equations and plug in for the other. So for this example: \[610x=y\] plug this into the other equation 340=4x2(610x) Does that help?
 one year ago
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