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zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \ln\left(\frac{\sqrt{x^2+1}}{x(2x^31)^2}\right)\] So this is what our problem looks like? Oh boy this one is gonna be a doozy. We'll have to apply the chain rule, and then the pruduct rule, and then the chain rule a few more times.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0The derivative of natural log gives us,\[\large \left(\ln \heartsuit\right)'=\frac{1}{\heartsuit}\heartsuit'\]I wanted to use some besides x, `Whatever` the contents of the log may be, you stuff all of that into the denominator. The prime on the outside is due to the chain rule. we have to multiply by the derivative of the inside of the log. The little prime is to let us know we still need to differentiate it. So if we apply this idea to our problem, here's what we get! :O

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large \frac{d}{dx}\ln\left(\frac{\sqrt{x^2+1}}{x(2x^31)^2}\right)\quad = \quad\] \[\large \frac{1}{\left(\frac{\sqrt{x^2+1}}{x(2x^31)^2}\right)}\frac{d}{dx}\left(\frac{\sqrt{x^2+1}}{x(2x^31)^2}\right)\]

dpaInc
 one year ago
Best ResponseYou've already chosen the best response.0looks like a lot of work... try simplifying \(\large ln(\frac{\sqrt{x^2+1}}{x(2x^31)^2}) \) using the properties of logs first...

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Ah yes, that would be better _ woops!
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