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ZeHanzBest ResponseYou've already chosen the best response.0
Begin with (7s ....)(s ....), because if you FOIL again, only 7s*s=7s² (F) But... that means the (L) last two numbers multiplied should be 5. That doesn't leave much options...
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
in a quadratic \[ax^2 + bx + c\] multiply a and c so in your question 7 *(5) = 35 find the factors of 35 that add to  2 ....... 7, 5 so them write your binomials as dw:1359919120501:dw remove the common factor from the 1st binomial and you'll see it cancels with the denominator so whats left is the answer.
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
Just experiment with 5 and 1 or 5 and 1...
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
oops should be s.... and the method works every time and easier than guess and check...
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.0
@rios0912bre: have you found the answer you were looking for?
 one year ago

rios0912breBest ResponseYou've already chosen the best response.0
havent worked the problem out yet since i gave up earlier but i will check it out here in a few thanks :)
 one year ago
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