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prove: sin y+tan y/ over /1+ sec y =sin y

Precalculus
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Like this? \(\dfrac{\sin y + \tan y}{1 + \sec y} = \sin y\)
yes
Start with this: \[ \dfrac{\sin y + \tan y}{1+\sec y} \cdot \dfrac{1-\sec y}{1-\sec y} \] Then multiply both fractions together then simplify.

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Other answers:

Get it?
yep
Oh, and remember these trigonometry identify: 1−sec²x = −tan²x
Please let me know when you are stuck, ok?
yea im bad at math so im stuck
In what step are you stuck at?
just cant do it

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