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 one year ago
idenify the definite integral that represents the area of the region bounded by the graphs of y=x and y=5xx^3
 one year ago
idenify the definite integral that represents the area of the region bounded by the graphs of y=x and y=5xx^3

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cherio12
 one year ago
Best ResponseYou've already chosen the best response.0try graphing them first to determine which function is the top and which is the bottom

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0still don't get it

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359920225466:dw

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1So ummmm yah that graph looks accurate. I always get confused by these types of problems. When the upper and lower functions switch places. But I think we can figure it out. Hmm.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Let's start by finding points of intersection.\[\large y=x \qquad y=5xx^3\qquad \qquad \rightarrow \qquad \qquad x=5xx^3\]

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Which turn out to be, \(\large x=0, \quad x=2, \quad x=2\).

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1Let's look at just the right side for a moment, maybe it will make a little more sense that way.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359921446750:dwSee how I've drawn a small rectangle? Let's find the area of that rectangle.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1The area will be `base x height`. The base has a thickness of \(dx\). The height is going to be `the upper function` minus `the lower function`.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large A=\left(height\right)(base)\]\[\large A=\left(5xx^3x\right)(dx)\]See how the line y=x is BELOW the other one? So we subtract y=x from the other function to get the correct height. So this represents the area of a small rectangular slice. Now we want to Integrate (sum up) all of the rectangles between these two curves.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1And we'll include our intersecting points.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \int\limits_0^2 4xx^3 \; dx\] This represents the area between the two curves on the RIGHT side. We still need to find the area of the other chunk. Notice how they switch places on the left? The line y=x is now the UPPER function! So we would subtract y=5xx^3 from the line y=x. And our limits of integration would be a little different.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.1There is a little trick we could pull though c: See how they're both odd functions? They're both symmetric about the origin. So the area on the left will be the same as the area on the right. We could simply multiply this integral by 2.\[\huge A_{total}\qquad =\qquad 2\int\limits\limits_0^2 4xx^3 \; dx\]

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0oh okay i see how you got that. thanks!
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