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Luigi0210

  • 3 years ago

A rectangle is bounded by the x and y axes and the graph of the line y= (-1/2)x+3. What length and width should the rectangle have so its area is maximum?

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  1. Luigi0210
    • 3 years ago
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    |dw:1359921377233:dw|

  2. anonymous
    • 3 years ago
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    base of rectangle will be \(x\) and height will be \(-\frac{1}{2}x+3\) so area is \[A(x)=x(-\frac{1}{2}x+3)=-\frac{1}{2}x^2+3x\]\]

  3. anonymous
    • 3 years ago
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    max will be at the vertex, which is at \(-\frac{b}{2a}=3\)

  4. Elsa213
    • one year ago
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    oooo a year later c: Heyo humans :D

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