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Luigi0210
A rectangle is bounded by the x and y axes and the graph of the line y= (-1/2)x+3. What length and width should the rectangle have so its area is maximum?
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base of rectangle will be \(x\) and height will be \(-\frac{1}{2}x+3\) so area is \[A(x)=x(-\frac{1}{2}x+3)=-\frac{1}{2}x^2+3x\]\]
max will be at the vertex, which is at \(-\frac{b}{2a}=3\)
oooo a year later c: Heyo humans :D