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amistre64
 one year ago
Best ResponseYou've already chosen the best response.0what does your graph look like?

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359922854861:dw

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0wait nevermind it's not that

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359922919356:dw thats what i was thinking it was like

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0then the only pertinent equations are: x^2x^4 and y=sqrt(x)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0they meet at x=0, and what is the other x value?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0sqrt(x) = x^2  x^4 0 = x^2 sqrt(x) x^4 that does seem a bit convoluted :/

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0hmmm, that is one representation i can see of it :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0so if thats the case, would changing it to parametric form help out?

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.2I'd: Write y as function of x: y=xsqrt(1x²) Integrate using u=1x² Multiply by 4, because of the symmetry...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0sounds crazy enough to work :)

jocelynevsq
 one year ago
Best ResponseYou've already chosen the best response.0what do I multiply by 4?

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.2If you integrate as I did, you only get the area between the positive xaxis and the graph (upper right part of the whole thing) There a 4 such areas, so multiply by 4.

ZeHanz
 one year ago
Best ResponseYou've already chosen the best response.2I've got to 8/3, hope this helps ;)
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