anonymous
  • anonymous
find the region bounded by the graph of y^2=x^2-x^4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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amistre64
  • amistre64
what does your graph look like?
anonymous
  • anonymous
|dw:1359922854861:dw|
anonymous
  • anonymous
i'm not sure

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anonymous
  • anonymous
wait nevermind it's not that
amistre64
  • amistre64
|dw:1359922919356:dw| thats what i was thinking it was like
anonymous
  • anonymous
yes
amistre64
  • amistre64
then the only pertinent equations are: x^2-x^4 and y=-sqrt(x)
amistre64
  • amistre64
they meet at x=0, and what is the other x value?
anonymous
  • anonymous
I don't know
amistre64
  • amistre64
-sqrt(x) = x^2 - x^4 0 = x^2 -sqrt(x) -x^4 that does seem a bit convoluted :/
ZeHanz
  • ZeHanz
Here's the graph:
1 Attachment
amistre64
  • amistre64
hmmm, that is one representation i can see of it :)
amistre64
  • amistre64
so if thats the case, would changing it to parametric form help out?
ZeHanz
  • ZeHanz
I'd: Write y as function of x: y=xsqrt(1-x²) Integrate using u=1-x² Multiply by 4, because of the symmetry...
amistre64
  • amistre64
sounds crazy enough to work :)
anonymous
  • anonymous
what do I multiply by 4?
ZeHanz
  • ZeHanz
If you integrate as I did, you only get the area between the positive x-axis and the graph (upper right part of the whole thing) There a 4 such areas, so multiply by 4.
anonymous
  • anonymous
oh okay thanks
ZeHanz
  • ZeHanz
I've got to 8/3, hope this helps ;)
anonymous
  • anonymous
thanks!

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