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anonymous
 3 years ago
find the region bounded by the graph of y^2=x^2x^4
anonymous
 3 years ago
find the region bounded by the graph of y^2=x^2x^4

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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0what does your graph look like?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359922854861:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wait nevermind it's not that

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1359922919356:dw thats what i was thinking it was like

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0then the only pertinent equations are: x^2x^4 and y=sqrt(x)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0they meet at x=0, and what is the other x value?

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0sqrt(x) = x^2  x^4 0 = x^2 sqrt(x) x^4 that does seem a bit convoluted :/

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0hmmm, that is one representation i can see of it :)

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0so if thats the case, would changing it to parametric form help out?

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.2I'd: Write y as function of x: y=xsqrt(1x²) Integrate using u=1x² Multiply by 4, because of the symmetry...

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0sounds crazy enough to work :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do I multiply by 4?

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.2If you integrate as I did, you only get the area between the positive xaxis and the graph (upper right part of the whole thing) There a 4 such areas, so multiply by 4.

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.2I've got to 8/3, hope this helps ;)
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