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jocelynevsq

find the region bounded by the graph of y^2=x^2-x^4

  • one year ago
  • one year ago

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  1. amistre64
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    what does your graph look like?

    • one year ago
  2. jocelynevsq
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    |dw:1359922854861:dw|

    • one year ago
  3. jocelynevsq
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    i'm not sure

    • one year ago
  4. jocelynevsq
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    wait nevermind it's not that

    • one year ago
  5. amistre64
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    |dw:1359922919356:dw| thats what i was thinking it was like

    • one year ago
  6. jocelynevsq
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    yes

    • one year ago
  7. amistre64
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    then the only pertinent equations are: x^2-x^4 and y=-sqrt(x)

    • one year ago
  8. amistre64
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    they meet at x=0, and what is the other x value?

    • one year ago
  9. jocelynevsq
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    I don't know

    • one year ago
  10. amistre64
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    -sqrt(x) = x^2 - x^4 0 = x^2 -sqrt(x) -x^4 that does seem a bit convoluted :/

    • one year ago
  11. ZeHanz
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    Here's the graph:

    • one year ago
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  12. amistre64
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    hmmm, that is one representation i can see of it :)

    • one year ago
  13. amistre64
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    so if thats the case, would changing it to parametric form help out?

    • one year ago
  14. ZeHanz
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    I'd: Write y as function of x: y=xsqrt(1-x²) Integrate using u=1-x² Multiply by 4, because of the symmetry...

    • one year ago
  15. amistre64
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    sounds crazy enough to work :)

    • one year ago
  16. jocelynevsq
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    what do I multiply by 4?

    • one year ago
  17. ZeHanz
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    If you integrate as I did, you only get the area between the positive x-axis and the graph (upper right part of the whole thing) There a 4 such areas, so multiply by 4.

    • one year ago
  18. jocelynevsq
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    oh okay thanks

    • one year ago
  19. ZeHanz
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    I've got to 8/3, hope this helps ;)

    • one year ago
  20. jocelynevsq
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    thanks!

    • one year ago
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