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sat_chenBest ResponseYou've already chosen the best response.0
dw:1359940501331:dw
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
Answer dw:1359940559335:dw
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
can someone just check if that is the right answer
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
im still kind of confused about it
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
i think you've made a mistake somewhere,
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
ok i did it wrong apparently but i dont know how to do it still :( ?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, denominator = x^2 (x4) do you know partial fractions method ? also, if you show your work, we can quickly spot the error, and continue from that step...
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
ok i will type it out for you
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
so first what i did was split the denominator to x(x^24) then split that to (x+2)(x2)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
then set the 2x^2 12x+4=A/x+B/(x+2)+C/(x2)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
here.... x^34x^2 = x^2 (x4) and not x (x^24)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
wow i cant believe i missed that
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
since you know partial fractions , i think you'll get it in your next try..
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
sorry guys my intentet is acting weird
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
yea ill try the steps again and after im done pm you the steps
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
to see if i did it right thanks
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, sure. or you can post it here.. welcome ^_^
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
so would the partial thing be Ax+ B /x^2 +C/(x4)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
and really sorrmy internet is going berserk for some reason today college inter is acting funky for some reason
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
wait isnt when the denominator is x^2 the top part is (Ax + B )/(x^2)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
its the same thing! (Ax+B)/x^2 = A/x + B/x^2
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
yep really had a long day today . after the superbowl drink and math dont go together
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
ok after im done ill post the answer ty
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
so 2x^212x+4 = A/x + B/x^2 +c/(x4)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
and i solved for c which got me 3/16
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
dw:1359956605483:dw
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
and i plugged in as x = 4;
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
to get c = 3/16 but you cant solve for the other A and B is there another method to do this? i dont get partial fractions
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
to find c, put x=4 to find b, put x=0 to find a, put x=any other value, say x=1
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
what part of partial fractions, do you not get ?
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
if you put x = 0 you will get all 3 = 0
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
dw:1359957041709:dw so you cant put 0
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
yea i got the c one though with is at x = 4
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
A x (x4) +B (x4) +C (x^2)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
dw:1359957163440:dw
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
wait can you tell me how you got that i got the trigonometric integral stuff but this stuff is confusing me
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
so can you tell me how you cancelled out the x in the B and the x in the A
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
shouldnt A/x be multiplied by dw:1359957703525:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
then denominator of A will become x^3 (x4) which we don't want and is not common
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
hold on what i meant was isnt the format dw:1359957835056:dw
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
dw:1359958002008:dw i guess what i mean is in this for example why did you only pick out x(x4) for A only (x4) for b and x^2 for C im really confused about that
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, that i have SAME denominator for all the 3.
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
and also because in previous problems i did it was like 4x^2 + 54 x + 134 = A/(x1) +B/(x+5) +C/(x+3) which i got to 4x^2 + 54x + 134 = A(x+5)(x+3) + B(x1)(x+3)+C(x1)(x+5)
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
do you have to do this when the denominator has a square on the x? or is it dependent on the problem
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
dw:1359958265843:dwits as simple as this...
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
oh i see i guess you could multiply what i did but it would cancel
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
i think i finally get it now
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
in previous problem, to make the common denominator as (x5)(x+5)(x+3) so, you multiplied and divided by (x+5)(x+3) for A yes, you can say that also...
 one year ago

sat_chenBest ResponseYou've already chosen the best response.0
now if i had payed attention in my algebra classes this would be so much easier .
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
no problem! because its easier for you now! right ?
 one year ago
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