A community for students.
Here's the question you clicked on:
 0 viewing
sat_chen
 2 years ago
did i get this partial integration question right?
sat_chen
 2 years ago
did i get this partial integration question right?

This Question is Closed

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0Answer dw:1359940559335:dw

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0can someone just check if that is the right answer

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0im still kind of confused about it

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0i think you've made a mistake somewhere,

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0ok i did it wrong apparently but i dont know how to do it still :( ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so, denominator = x^2 (x4) do you know partial fractions method ? also, if you show your work, we can quickly spot the error, and continue from that step...

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0ok i will type it out for you

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0so first what i did was split the denominator to x(x^24) then split that to (x+2)(x2)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0then set the 2x^2 12x+4=A/x+B/(x+2)+C/(x2)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1here.... x^34x^2 = x^2 (x4) and not x (x^24)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0wow i cant believe i missed that

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1since you know partial fractions , i think you'll get it in your next try..

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0sorry guys my intentet is acting weird

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0yea ill try the steps again and after im done pm you the steps

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0to see if i did it right thanks

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1ok, sure. or you can post it here.. welcome ^_^

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0so would the partial thing be Ax+ B /x^2 +C/(x4)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and really sorrmy internet is going berserk for some reason today college inter is acting funky for some reason

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0wait isnt when the denominator is x^2 the top part is (Ax + B )/(x^2)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1its the same thing! (Ax+B)/x^2 = A/x + B/x^2

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0yep really had a long day today . after the superbowl drink and math dont go together

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0ok after im done ill post the answer ty

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0so 2x^212x+4 = A/x + B/x^2 +c/(x4)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and i solved for c which got me 3/16

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and i plugged in as x = 4;

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0to get c = 3/16 but you cant solve for the other A and B is there another method to do this? i dont get partial fractions

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1to find c, put x=4 to find b, put x=0 to find a, put x=any other value, say x=1

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1what part of partial fractions, do you not get ?

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0if you put x = 0 you will get all 3 = 0

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359957041709:dw so you cant put 0

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0yea i got the c one though with is at x = 4

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1A x (x4) +B (x4) +C (x^2)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0wait can you tell me how you got that i got the trigonometric integral stuff but this stuff is confusing me

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0so can you tell me how you cancelled out the x in the B and the x in the A

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0shouldnt A/x be multiplied by dw:1359957703525:dw

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1then denominator of A will become x^3 (x4) which we don't want and is not common

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0hold on what i meant was isnt the format dw:1359957835056:dw

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1359958002008:dw i guess what i mean is in this for example why did you only pick out x(x4) for A only (x4) for b and x^2 for C im really confused about that

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1so, that i have SAME denominator for all the 3.

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0and also because in previous problems i did it was like 4x^2 + 54 x + 134 = A/(x1) +B/(x+5) +C/(x+3) which i got to 4x^2 + 54x + 134 = A(x+5)(x+3) + B(x1)(x+3)+C(x1)(x+5)

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0do you have to do this when the denominator has a square on the x? or is it dependent on the problem

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1359958265843:dwits as simple as this...

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0oh i see i guess you could multiply what i did but it would cancel

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0i think i finally get it now

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1in previous problem, to make the common denominator as (x5)(x+5)(x+3) so, you multiplied and divided by (x+5)(x+3) for A yes, you can say that also...

sat_chen
 2 years ago
Best ResponseYou've already chosen the best response.0now if i had payed attention in my algebra classes this would be so much easier .

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.1no problem! because its easier for you now! right ?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.