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sat_chen Group TitleBest ResponseYou've already chosen the best response.0
dw:1359940501331:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
Answer dw:1359940559335:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
can someone just check if that is the right answer
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
im still kind of confused about it
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
i think you've made a mistake somewhere,
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
ok i did it wrong apparently but i dont know how to do it still :( ?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, denominator = x^2 (x4) do you know partial fractions method ? also, if you show your work, we can quickly spot the error, and continue from that step...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
ok i will type it out for you
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
so first what i did was split the denominator to x(x^24) then split that to (x+2)(x2)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
then set the 2x^2 12x+4=A/x+B/(x+2)+C/(x2)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
here.... x^34x^2 = x^2 (x4) and not x (x^24)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
wow i cant believe i missed that
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
since you know partial fractions , i think you'll get it in your next try..
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
sorry guys my intentet is acting weird
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
yea ill try the steps again and after im done pm you the steps
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
to see if i did it right thanks
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, sure. or you can post it here.. welcome ^_^
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
so would the partial thing be Ax+ B /x^2 +C/(x4)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
and really sorrmy internet is going berserk for some reason today college inter is acting funky for some reason
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
A/x+ B /x^2 +C/(x4)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
wait isnt when the denominator is x^2 the top part is (Ax + B )/(x^2)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
its the same thing! (Ax+B)/x^2 = A/x + B/x^2
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
yep really had a long day today . after the superbowl drink and math dont go together
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
ok after im done ill post the answer ty
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
so 2x^212x+4 = A/x + B/x^2 +c/(x4)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
and i solved for c which got me 3/16
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
dw:1359956605483:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
and i plugged in as x = 4;
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
to get c = 3/16 but you cant solve for the other A and B is there another method to do this? i dont get partial fractions
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
to find c, put x=4 to find b, put x=0 to find a, put x=any other value, say x=1
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
what part of partial fractions, do you not get ?
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
if you put x = 0 you will get all 3 = 0
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
dw:1359957041709:dw so you cant put 0
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
yea i got the c one though with is at x = 4
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
......+B (x4)+.....
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
A x (x4) +B (x4) +C (x^2)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
dw:1359957163440:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
wait can you tell me how you got that i got the trigonometric integral stuff but this stuff is confusing me
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
so can you tell me how you cancelled out the x in the B and the x in the A
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359957466093:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359957564998:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
shouldnt A/x be multiplied by dw:1359957703525:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
then denominator of A will become x^3 (x4) which we don't want and is not common
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
hold on what i meant was isnt the format dw:1359957835056:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
dw:1359958002008:dw i guess what i mean is in this for example why did you only pick out x(x4) for A only (x4) for b and x^2 for C im really confused about that
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
so, that i have SAME denominator for all the 3.
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
and also because in previous problems i did it was like 4x^2 + 54 x + 134 = A/(x1) +B/(x+5) +C/(x+3) which i got to 4x^2 + 54x + 134 = A(x+5)(x+3) + B(x1)(x+3)+C(x1)(x+5)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
do you have to do this when the denominator has a square on the x? or is it dependent on the problem
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359958265843:dwits as simple as this...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
oh i see i guess you could multiply what i did but it would cancel
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
i think i finally get it now
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
in previous problem, to make the common denominator as (x5)(x+5)(x+3) so, you multiplied and divided by (x+5)(x+3) for A yes, you can say that also...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
now if i had payed attention in my algebra classes this would be so much easier .
 one year ago