did i get this partial integration question right?

- anonymous

did i get this partial integration question right?

- schrodinger

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- anonymous

|dw:1359940501331:dw|

- anonymous

Answer
|dw:1359940559335:dw|

- anonymous

can someone just check if that is the right answer

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## More answers

- anonymous

im still kind of confused about it

- UnkleRhaukus

i think you've made a mistake somewhere,

- anonymous

ok i did it wrong apparently but i dont know how to do it still :( ?

- hartnn

so, denominator = x^2 (x-4)
do you know partial fractions method ?
also, if you show your work, we can quickly spot the error, and continue from that step...

- anonymous

ok i will type it out for you

- anonymous

so first what i did was split the denominator to x(x^2-4)
then split that to (x+2)(x-2)

- anonymous

then set the 2x^2 -12x+4=A/x+B/(x+2)+C/(x-2)

- hartnn

here....
x^3-4x^2 = x^2 (x-4)
and not x (x^2-4)

- anonymous

wow i cant believe i missed that

- hartnn

since you know partial fractions , i think you'll get it in your next try..

- anonymous

sorry guys my intentet is acting weird

- anonymous

yea ill try the steps again and after im done pm you the steps

- anonymous

to see if i did it right thanks

- hartnn

ok, sure.
or you can post it here..
welcome ^_^

- anonymous

so would the partial thing be Ax+ B /x^2 +C/(x-4)

- hartnn

yes.

- anonymous

and really sorrmy internet is going berserk for some reason today college inter is acting funky for some reason

- hartnn

A/x+ B /x^2 +C/(x-4)

- anonymous

wait isnt when the denominator is x^2 the top part is (Ax + B )/(x^2)

- hartnn

its the same thing!
(Ax+B)/x^2 = A/x + B/x^2

- anonymous

yep really had a long day today -.- after the superbowl drink and math dont go together

- hartnn

lol.

- anonymous

ok after im done ill post the answer ty

- anonymous

so 2x^2-12x+4 = A/x + B/x^2 +c/(x-4)

- anonymous

and i solved for c which got me -3/16

- anonymous

|dw:1359956605483:dw|

- anonymous

and i plugged in as x = 4;

- anonymous

to get c = -3/16 but you cant solve for the other A and B is there another method to do this? i dont get partial fractions

- hartnn

to find c, put x=4
to find b, put x=0
to find a, put x=any other value, say x=1

- hartnn

what part of partial fractions, do you not get ?

- anonymous

if you put x = 0 you will get all 3 = 0

- hartnn

u sure ?

- anonymous

|dw:1359957041709:dw| so you cant put 0

- anonymous

yea i got the c one though with is at x = 4

- hartnn

......+B (x-4)+.....

- hartnn

A x (x-4) +B (x-4) +C (x^2)

- anonymous

|dw:1359957163440:dw|

- anonymous

wait can you tell me how you got that i got the trigonometric integral stuff but this stuff is confusing me

- anonymous

so can you tell me how you cancelled out the x in the B and the x in the A

- hartnn

|dw:1359957466093:dw|

- hartnn

|dw:1359957564998:dw|

- anonymous

shouldnt A/x be multiplied by |dw:1359957703525:dw|

- hartnn

then denominator of A will become x^3 (x-4)
which we don't want and is not common

- anonymous

hold on what i meant was isnt the format |dw:1359957835056:dw|

- anonymous

|dw:1359958002008:dw|
i guess what i mean is in this for example why did you only pick out x(x-4) for A only (x-4) for b and x^2 for C im really confused about that

- hartnn

so, that i have SAME denominator for all the 3.

- anonymous

and also because in previous problems i did it was like 4x^2 + 54 x + 134 = A/(x-1) +B/(x+5) +C/(x+3)
which i got to 4x^2 + 54x + 134 = A(x+5)(x+3) + B(x-1)(x+3)+C(x-1)(x+5)

- anonymous

do you have to do this when the denominator has a square on the x? or is it dependent on the problem

- hartnn

|dw:1359958265843:dw|its as simple as this...

- hartnn

do what ?

- anonymous

oh i see i guess you could multiply what i did but it would cancel

- anonymous

i think i finally get it now

- hartnn

in previous problem, to make the common denominator as (x-5)(x+5)(x+3)
so, you multiplied and divided by (x+5)(x+3) for A
yes, you can say that also...

- anonymous

now if i had payed attention in my algebra classes this would be so much easier -.-

- hartnn

no problem! because its easier for you now! right ?

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