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sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359940501331:dw

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0Answer dw:1359940559335:dw

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0can someone just check if that is the right answer

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0im still kind of confused about it

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0i think you've made a mistake somewhere,

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0ok i did it wrong apparently but i dont know how to do it still :( ?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, denominator = x^2 (x4) do you know partial fractions method ? also, if you show your work, we can quickly spot the error, and continue from that step...

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0ok i will type it out for you

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0so first what i did was split the denominator to x(x^24) then split that to (x+2)(x2)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0then set the 2x^2 12x+4=A/x+B/(x+2)+C/(x2)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1here.... x^34x^2 = x^2 (x4) and not x (x^24)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0wow i cant believe i missed that

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1since you know partial fractions , i think you'll get it in your next try..

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0sorry guys my intentet is acting weird

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0yea ill try the steps again and after im done pm you the steps

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0to see if i did it right thanks

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, sure. or you can post it here.. welcome ^_^

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0so would the partial thing be Ax+ B /x^2 +C/(x4)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0and really sorrmy internet is going berserk for some reason today college inter is acting funky for some reason

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0wait isnt when the denominator is x^2 the top part is (Ax + B )/(x^2)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1its the same thing! (Ax+B)/x^2 = A/x + B/x^2

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0yep really had a long day today . after the superbowl drink and math dont go together

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0ok after im done ill post the answer ty

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0so 2x^212x+4 = A/x + B/x^2 +c/(x4)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0and i solved for c which got me 3/16

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359956605483:dw

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0and i plugged in as x = 4;

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0to get c = 3/16 but you cant solve for the other A and B is there another method to do this? i dont get partial fractions

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1to find c, put x=4 to find b, put x=0 to find a, put x=any other value, say x=1

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1what part of partial fractions, do you not get ?

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0if you put x = 0 you will get all 3 = 0

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359957041709:dw so you cant put 0

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0yea i got the c one though with is at x = 4

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1A x (x4) +B (x4) +C (x^2)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359957163440:dw

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0wait can you tell me how you got that i got the trigonometric integral stuff but this stuff is confusing me

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0so can you tell me how you cancelled out the x in the B and the x in the A

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0shouldnt A/x be multiplied by dw:1359957703525:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1then denominator of A will become x^3 (x4) which we don't want and is not common

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0hold on what i meant was isnt the format dw:1359957835056:dw

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0dw:1359958002008:dw i guess what i mean is in this for example why did you only pick out x(x4) for A only (x4) for b and x^2 for C im really confused about that

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, that i have SAME denominator for all the 3.

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0and also because in previous problems i did it was like 4x^2 + 54 x + 134 = A/(x1) +B/(x+5) +C/(x+3) which i got to 4x^2 + 54x + 134 = A(x+5)(x+3) + B(x1)(x+3)+C(x1)(x+5)

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0do you have to do this when the denominator has a square on the x? or is it dependent on the problem

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359958265843:dwits as simple as this...

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0oh i see i guess you could multiply what i did but it would cancel

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0i think i finally get it now

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1in previous problem, to make the common denominator as (x5)(x+5)(x+3) so, you multiplied and divided by (x+5)(x+3) for A yes, you can say that also...

sat_chen
 one year ago
Best ResponseYou've already chosen the best response.0now if i had payed attention in my algebra classes this would be so much easier .

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1no problem! because its easier for you now! right ?
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