Calculus 2 problem. Help please.
y=e^x, y=e^2x, x=ln2, x=0
Find the area enclosed by the curves. Show steps please.

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\[A = \int\limits_{0}^{\ln(2)} (e^{2x} - e^{x}) dx\]

Right, but what is the actual area. That's where I am having trouble. thanks.

The answer is supposed to be 1/2, but I am not getting that.

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