anonymous
  • anonymous
Multiply the polynomials: 1. (a + 3)(a - 2) 2. (x2 + 4)(x2 - 4) 3. (x2 + 3x + 1)(x2 + x + 2)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
use the distributive property \[a(b\pm c)=ab\pm ac\]
anonymous
  • anonymous
using this you take the first variable of the first and multiply it by the second parenthesis and same with the second variable/constant of the first \[a(a-2)+3(a-2)\]
anonymous
  • anonymous
what do you get when yo udo this?

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anonymous
  • anonymous
So then i got: 2a-2a + 3a-6
anonymous
  • anonymous
But I dont think that is right lol
anonymous
  • anonymous
@Outkast3r09
anonymous
  • anonymous
everything but your first multiplication is correct \[a(a)\neq 2a\]
anonymous
  • anonymous
hint: when you have a number to a power you get this correct \[2^2=2*2\]
anonymous
  • anonymous
so \[a*a=?\]
anonymous
  • anonymous
uhhh 2 squared ???
anonymous
  • anonymous
@Outkast3r09
anonymous
  • anonymous
not quite so 2 is the base
anonymous
  • anonymous
in \[2^2\]
anonymous
  • anonymous
the power tells you how many times you multiply that base by itself
anonymous
  • anonymous
so \[2^3=2*2*2\] \[2^5=2*2*2*2*2\]
anonymous
  • anonymous
so in your case \[ a*a\] a is your base and the number of bases you multiply is your power
anonymous
  • anonymous
so \[a*a=a^2\]
anonymous
  • anonymous
I know how to do powers lol. I just dont know what \[a \times a\] is
anonymous
  • anonymous
oh okay lol
anonymous
  • anonymous
|dw:1359943457681:dw|
anonymous
  • anonymous
I think it's just the variable thats giving you a tough time if it helps let a be whatever you want and then replace it back with a. For example i have \[a*a*a*a\] in your head think a=5 \[5*5*5*5=5^4\] replace 5 with a
anonymous
  • anonymous
|dw:1359943594086:dw|
anonymous
  • anonymous
some someone let her do the last one
anonymous
  • anonymous
so would it be \[a ^{2}-5a -6\] ?
anonymous
  • anonymous
\[-2a+3a\] if you have 3 dollars and lost 2 dollars, how many do you have now =]
anonymous
  • anonymous
lol 1 dollar
anonymous
  • anonymous
|dw:1359943710986:dw|
anonymous
  • anonymous
|dw:1359943887804:dw|
anonymous
  • anonymous
Thank you thank you thank you @Outkast3r09 and @some_someone !!!!
anonymous
  • anonymous
your welcome hope we could help you :)

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