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anonymous
 3 years ago
I need to know if I use the Poisson Distribution for problem 5 (AC).
anonymous
 3 years ago
I need to know if I use the Poisson Distribution for problem 5 (AC).

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No use the Binomial distribution p= 1/3 for tie p=1/6 for "00" tie

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i would use this formula: P^k * (1p)^nk and for part A, I would plug in 10 for n and 3 for k???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 @karatechopper @JuanitaM

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://en.wikipedia.org/wiki/Binomial_distribution#Probability_mass_function

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so im correct. woohoo! :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, so i get .0021676912. is that the final answer or is there anything else i needa do?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for part A ? i get about 0.26

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah, how'd u get .26 ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just plugged numbers in formula ... well i cheated and used Excel :) p = 1/3 n=10 k=3 \[\rightarrow \left(\begin{matrix}10 \\ 3\end{matrix}\right)*(\frac{1}{3})^{3} *(\frac{2}{3})^{7} = 120*\frac{128}{3^{10}} = 0.2601\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im confused about the second half... after the first equal sign

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}10 \\ 3\end{matrix}\right) = \frac{10!}{7! 3!} = 120\] \[(\frac{1}{3})^{3} *(\frac{2}{3})^{7} = \frac{1}{3^{3}}*\frac{2^{7}}{3^{7}} = \frac{2^{7}}{3^{10}} = \frac{128}{59,049}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok. so i was getting .0021676912 because i didn't multiply it by 120. makes sense.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so for part B i would just change p to 1/6 ??? (why 1/6 again?) and for part C i would do 1part B ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its 1/6 because its half of 1/3 > 1/3 * 1/2 = 1/6 part C is looking at chance you tie but Not 00 > 1/3  1/6 = 1/6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0o because half would equal zerozero ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and part Cs answer will basically be the same as part B since they're both p=1/6?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0umm yep thats what it looks like

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0alright, so im on #7 and it's wanting the same info as #6 but normally distributed... would i use : f(x)= ( 1 / [sigma * sqrt(2pi)] ) * e ^ (xmu/sigma) to plug in the same info from 6???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0here are the answers to #6: a) picture b) 1/(ba) = 1/(210150) = 1/60 c) (160150)/(210150) = 10/60 = 1/6 d) 1/6 * 1/6 = 1/36 e) (185165)/(210150) = 20/60 = 2/6 f) (210200)/(210150) = 10/60 = 1/6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360115375877:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes that is the function for normal distribution but since its complex....you need to use probability table for normal distribution problems you have to determine zscore (standardized value) first anyway, check your answers from #6 again first though the mean has to be a number between 150 and 210 .... not 1/60

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got 1/60 by using the formula but i guess thats not correct since it makes no sense to have a mean of 1/60. i guess the mean is 180 ( 150+210 / 2 )

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@satellite73 can you continue where @dumbcow left off??? they are no longer online. :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.04 is poisson, 5 is binomial

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what number are you on?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it's asking me to repeat the steps of #6 but idk what to really do

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0damn i don't know squat about the normal distribution sorry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its like the picture i drew above ^^^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know, but you need a table to calculate these

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the mean is 180 right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes and the standard deviation is 20

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you need to convert to a z score or something right? so you can look these up in a table

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for example \[\frac{165180}{20}=.75\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and \[\frac{185180}{20}=.25\] so you need to use a table to find the area under the normal curve between \(.75\) and \(.25\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can use this http://www.danielsoper.com/statcalc3/calc.aspx?id=2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont think thats how it works... are both sides supposed to be equal but opposite?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0not unless they happen to be your question is between 165 and 185 which is not symmetric about 180 it is 5 up and 10 down

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so your job is to find the area under the curve from .75 to .25 this takes a couple steps

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0from the table , to the left of .25 is 0.59870633 and to the left of .75 is 0.2266273 so you use \[0.598706330.2266273\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the normal curve is symmetric the way the tables work is that they give you the area under the curve to the left of your z score so if you want the area between two z scores you take the larger z score, find the area in a table, then take the smaller area, and subtract

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360121214382:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360121361823:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0area between .75 and .25 is what you want it is the area to the left of .25 minus the area to the left of .75

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i see what you are doing

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0site is freezing up on me, but you can use the calculator i linked to find the z scores, then the area you want

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so we get 0.37207903 or 37% chance ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am having trouble scrolling up, but i did find the numbers you need, i just didn't subtract

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah that looks right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you assist me with #8 too?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360121910130:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where do i go from here??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0we got to look in a table and see what the right hand point give 97.5 % of the area (so the left hand point will have 2.5% and the area between them will be 95%

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh forget what i wrote above you just need to go to 95% short people can sit anyway

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0im confused. can you reword.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think 95% of the people lie within two standard deviations of the mean, meaning if you look at the table you should see for .95 a z score of 2 you have to check this because i do not have a table if this is true, then two standard deviations is 40 and 180 + 40 = 120 is the max height

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0are talking about this table? http://assets.openstudy.com/updates/attachments/5061f687e4b0583d5cd2e54cmahlatse11348604740357standardnormaltable.pdf

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we find .95 in the table, and see what the corresponding z score is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0looks like about 1.64 or 1.65 half way between them actually lets pick one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for the sake of argument, lets say the z score is 1.64 then we convert back to height \[1.64\times 20+180\] will give what we want

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0remember we computed the z score for say \(x\) by \[\frac{x180}{20}\] so if \[\frac{x180}{20}=1.64\] then \[x=1.64\times 20+180\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats the final answer??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i forgot what the question was can you repost so i don't have to keep scrolling down?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nvm the limit of the height adjustment is what you wanted so yes, that should be the answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0should i solve or leave as is

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0of course they want a number i would say about 213 or so

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the next one is similar find .98 in the body of the table, find the corresponding z score and work backwards to find the height

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i got 221 as my final answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0looks like a z score of about 2.05 there is nothing really profound about this, it just says that 98% are less than 2.05 standard deviations above the mean since the standard deviation is 20 and the mean is 180 that means 98% are under \(2.05\times 20+180=221\) cm tall

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i go the same thing gotta run good luck!
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