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Use a proof by cases to show that min(a , min(b, c» =
min(min(a , b) , c) whenever a, b, and c are real numbers.
 one year ago
 one year ago
Use a proof by cases to show that min(a , min(b, c» = min(min(a , b) , c) whenever a, b, and c are real numbers.
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
i guess you can grind it out with cases, for example if \(a\leq b\leq c\) then \[\min(a, (\min(b,c))=\min(a, b)=a\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
similarly if \(a\leq c\leq b\) then \(\min(a,\min(b,c))=\min(a,c)=a\) and so on
 one year ago

wingsoflightBest ResponseYou've already chosen the best response.0
thank you for clear answer
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
oh i guess you have to say for the first one that \(\min(a, \min(b,c))=a=\min(\min(a,b),c)\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
likewise for the second. there may be a snappier way to do this, but it did say by cases, so just grind it out
 one year ago
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