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wingsoflight
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Use a proof by cases to show that min(a , min(b, c» =
min(min(a , b) , c) whenever a, b, and c are real numbers.
 one year ago
 one year ago
wingsoflight Group Title
Use a proof by cases to show that min(a , min(b, c» = min(min(a , b) , c) whenever a, b, and c are real numbers.
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i guess you can grind it out with cases, for example if \(a\leq b\leq c\) then \[\min(a, (\min(b,c))=\min(a, b)=a\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
similarly if \(a\leq c\leq b\) then \(\min(a,\min(b,c))=\min(a,c)=a\) and so on
 one year ago

wingsoflight Group TitleBest ResponseYou've already chosen the best response.0
thank you for clear answer
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
oh i guess you have to say for the first one that \(\min(a, \min(b,c))=a=\min(\min(a,b),c)\)
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
likewise for the second. there may be a snappier way to do this, but it did say by cases, so just grind it out
 one year ago
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