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Shaydenparis

  • 3 years ago

prove siny +tany/over/ 1+secy=siny

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  1. geerky42
    • 3 years ago
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    \(\dfrac{\sin y + \tan y}{1 + \sec y} \Rightarrow \dfrac{\sin y + \tan y}{1 + \sec y} \cdot \dfrac{1 - \sec y}{1 - \sec y} = \dfrac{(\sin y + \tan y)(1 - \sec y)}{1 - \sec^2 y} \) Can you do the next step?

  2. Shaydenparis
    • 3 years ago
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    yep i got it, thank you

  3. terenzreignz
    • 3 years ago
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    For some reason, I don't really see how this helps... better to express everything in terms of sin and cos instead... oh well.

  4. terenzreignz
    • 3 years ago
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    \[\huge \frac{\sin y + \frac{\sin y}{\cos y}}{1 + \frac{1}{\cos y}}\]

  5. terenzreignz
    • 3 years ago
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    \[\huge \frac{\frac{\sin y \cos y + \sin y}{\cos y}}{\frac{\cos y + 1}{\cos y}}\]

  6. terenzreignz
    • 3 years ago
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    \[\large \frac{\sin y \cos y + \sin y}{\cos y + 1}=\frac{(\sin y)(\cos y + 1)}{\cos y + 1}\] And now it should be easy to see.

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