anonymous
  • anonymous
prove siny +tany/over/ 1+secy=siny
Mathematics
chestercat
  • chestercat
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geerky42
  • geerky42
\(\dfrac{\sin y + \tan y}{1 + \sec y} \Rightarrow \dfrac{\sin y + \tan y}{1 + \sec y} \cdot \dfrac{1 - \sec y}{1 - \sec y} = \dfrac{(\sin y + \tan y)(1 - \sec y)}{1 - \sec^2 y} \) Can you do the next step?
anonymous
  • anonymous
yep i got it, thank you
terenzreignz
  • terenzreignz
For some reason, I don't really see how this helps... better to express everything in terms of sin and cos instead... oh well.

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terenzreignz
  • terenzreignz
\[\huge \frac{\sin y + \frac{\sin y}{\cos y}}{1 + \frac{1}{\cos y}}\]
terenzreignz
  • terenzreignz
\[\huge \frac{\frac{\sin y \cos y + \sin y}{\cos y}}{\frac{\cos y + 1}{\cos y}}\]
terenzreignz
  • terenzreignz
\[\large \frac{\sin y \cos y + \sin y}{\cos y + 1}=\frac{(\sin y)(\cos y + 1)}{\cos y + 1}\] And now it should be easy to see.

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