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hrcheerlove

  • 3 years ago

1. 8y 7 ÷ 4y 5 2. (18x 5 + 6x 4 - 12x 3) ÷ 6x 2 helppppp???

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  1. Outkast3r09
    • 3 years ago
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    \[\frac{x^n}{x^m}=x^{n-m}\]

  2. hrcheerlove
    • 3 years ago
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    huh ?

  3. Outkast3r09
    • 3 years ago
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    so first take care of the constants, \[\frac{8}{4}=\]

  4. hrcheerlove
    • 3 years ago
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    2

  5. Outkast3r09
    • 3 years ago
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    then you have \[\frac{y^7}{y^5}\] since they have the same base you can use the above property so \[\frac{y^7}{y^5}=y^{7-5}\]

  6. Outkast3r09
    • 3 years ago
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    so combine your constant and your variables to get \[2y^{7-5}=2y^2\]

  7. hrcheerlove
    • 3 years ago
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    \[ (18x ^{5}+6x ^{4}-12x ^{3})\div6x ^{2} \] is the q btw it didnt post the powers

  8. Outkast3r09
    • 3 years ago
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    the second equation you need to split everything up into their own fractions

  9. hrcheerlove
    • 3 years ago
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    same for the first one

  10. hrcheerlove
    • 3 years ago
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    I have no idea how to do this

  11. Outkast3r09
    • 3 years ago
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    so \[\frac{18x^5+6x^4-12x^3}{6x^2}=\frac{18x^5}{6x^2}+\frac{6x^4}{6x^2}-\frac{12x^3}{6x^2}\]

  12. Outkast3r09
    • 3 years ago
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    then do what we did in the first one

  13. hrcheerlove
    • 3 years ago
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    Still have no idea lol

  14. hrcheerlove
    • 3 years ago
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    Thanks guys

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