## anonymous 3 years ago 1. 8y 7 ÷ 4y 5 2. (18x 5 + 6x 4 - 12x 3) ÷ 6x 2 helppppp???

1. anonymous

$\frac{x^n}{x^m}=x^{n-m}$

2. anonymous

huh ?

3. anonymous

so first take care of the constants, $\frac{8}{4}=$

4. anonymous

2

5. anonymous

then you have $\frac{y^7}{y^5}$ since they have the same base you can use the above property so $\frac{y^7}{y^5}=y^{7-5}$

6. anonymous

so combine your constant and your variables to get $2y^{7-5}=2y^2$

7. anonymous

$(18x ^{5}+6x ^{4}-12x ^{3})\div6x ^{2}$ is the q btw it didnt post the powers

8. anonymous

the second equation you need to split everything up into their own fractions

9. anonymous

same for the first one

10. anonymous

I have no idea how to do this

11. anonymous

so $\frac{18x^5+6x^4-12x^3}{6x^2}=\frac{18x^5}{6x^2}+\frac{6x^4}{6x^2}-\frac{12x^3}{6x^2}$

12. anonymous

then do what we did in the first one

13. anonymous

Still have no idea lol

14. anonymous

Thanks guys