hrcheerlove
1. 8y 7 ÷ 4y 5
2. (18x 5 + 6x 4  12x 3) ÷ 6x 2 helppppp???



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Outkast3r09
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\[\frac{x^n}{x^m}=x^{nm}\]

hrcheerlove
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huh ?

Outkast3r09
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so first take care of the constants,
\[\frac{8}{4}=\]

hrcheerlove
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2

Outkast3r09
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then you have
\[\frac{y^7}{y^5}\]
since they have the same base you can use the above property
so
\[\frac{y^7}{y^5}=y^{75}\]

Outkast3r09
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so combine your constant and your variables to get
\[2y^{75}=2y^2\]

hrcheerlove
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\[ (18x ^{5}+6x ^{4}12x ^{3})\div6x ^{2} \] is the q btw it didnt post the powers

Outkast3r09
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the second equation you need to split everything up into their own fractions

hrcheerlove
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same for the first one

hrcheerlove
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I have no idea how to do this

Outkast3r09
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so
\[\frac{18x^5+6x^412x^3}{6x^2}=\frac{18x^5}{6x^2}+\frac{6x^4}{6x^2}\frac{12x^3}{6x^2}\]

Outkast3r09
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then do what we did in the first one

hrcheerlove
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Still have no idea lol

hrcheerlove
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Thanks guys