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nyland1

  • 3 years ago

How many grams of H2 are needed produced in 11.13 grams of of NH3

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  1. aaronq
    • 3 years ago
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    can you write an equation for the reaction and balance it?

  2. nyland1
    • 3 years ago
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    3H2+N2\[3H _{2}+N _{2}\rightarrow2NH _{3}\]

  3. nyland1
    • 3 years ago
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    ignore the first part

  4. aaronq
    • 3 years ago
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    okay good stuff, now covert the grams of NH3 to moles

  5. nyland1
    • 3 years ago
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    ok so find the molar mass?

  6. aaronq
    • 3 years ago
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    well yeah, then find the moles moles=mass/molar mass

  7. nyland1
    • 3 years ago
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    17.034

  8. nyland1
    • 3 years ago
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    .653

  9. aaronq
    • 3 years ago
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    okay so you have this 3H2+N2→2NH3 x 0.653 now, you have to use the coefficients to form a ratio between the 2 substances, since they're not in a one to one relationship. aA + bB -> cC moles of C/c = moles of A/a

  10. nyland1
    • 3 years ago
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    see i dont understand that

  11. aaronq
    • 3 years ago
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    all you have to do is normalize each one by diving the amount of moles by it's respective coefficient \[\frac{ moles of H _{2} }{ 3 }=\frac{ moles of NH _{3} }{ 2 }\]

  12. aaronq
    • 3 years ago
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    then solve for whatever you're looking for

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