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How many grams of H2 are needed produced in 11.13 grams of of NH3

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can you write an equation for the reaction and balance it?
3H2+N2\[3H _{2}+N _{2}\rightarrow2NH _{3}\]
ignore the first part

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okay good stuff, now covert the grams of NH3 to moles
ok so find the molar mass?
well yeah, then find the moles moles=mass/molar mass
okay so you have this 3H2+N2→2NH3 x 0.653 now, you have to use the coefficients to form a ratio between the 2 substances, since they're not in a one to one relationship. aA + bB -> cC moles of C/c = moles of A/a
see i dont understand that
all you have to do is normalize each one by diving the amount of moles by it's respective coefficient \[\frac{ moles of H _{2} }{ 3 }=\frac{ moles of NH _{3} }{ 2 }\]
then solve for whatever you're looking for

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