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Multiply it out.

did that, but how do you separate the xy term?

This has to be implicitly differentiated

oh sorry , i plugged in 4 for C in wolfram example

You figure this one out yet zon? :D

I am putting it in that graphing calculator now to see if it worked.

well i guess i did something wrong,
i ended up getting ln y - ln x = C

and it wont let me graph that.

Try graphing that blue one maybe :o hmm

Where are these natural logs coming from? :D I don't understand what you did XD

??
i have graph in wolfram link

yah it sure didn't :( hmm

???
integral ... i thought the point was to find dy/dx

back where it was y' = y/x, it needed to be -1/y' = y/x

so now i get 1/2x^2 + 1/2y^2 = C

sweet, it worked...

oh cool! c:

im trying to get the link of the graph in here

Upper right corner, theres a blue button, it's a like...a square with an arrow in it

https://s3.amazonaws.com/grapher/exports/vg28uobv4e.png