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P.nut1996
 3 years ago
Please help me solve?
I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...
P.nut1996
 3 years ago
Please help me solve? I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...

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P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0\[2\sqrt{44x ^{3}}\sqrt{7}\sqrt{99x ^{3}}+\sqrt{63}\]

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Combine like terms, right? I don't see how to combine \[2\sqrt{44x ^{3}}\] and \[\sqrt{99x ^{3}}\]

javawarrior
 3 years ago
Best ResponseYou've already chosen the best response.0before combining see if you can simplify each term first

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Oh! like 11 goes into both 44 and 99??

javawarrior
 3 years ago
Best ResponseYou've already chosen the best response.0see if u can get rid of the roots!

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0How would I go about doing that? Right now I have \[2\sqrt{4x ^{3}}\sqrt{7}\sqrt{9x ^{3}}+\sqrt{63}\]

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Does it look right? Going in the right direction maybe?

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, and I eliminated 7. and the sqrt of 63 is now the sqrt of 9

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt {63} = \sqrt {9} \sqrt {7}=...?\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Now it looks like \[2\sqrt{4x ^{3}}\sqrt{9x ^{3}}+\sqrt{9}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...?\) you just can't eliminate 7...

Andresfon12
 3 years ago
Best ResponseYou've already chosen the best response.0something is missing

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...? \\\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0But & goes into 7 one time and it goes into 63 9 times. Simplifying... Right?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, \(\sqrt {63}\sqrt 7 = \sqrt{9}\sqrt{7}\sqrt{7} = \sqrt{7}[31]=..?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1you see what i did there ^ ?

Andresfon12
 3 years ago
Best ResponseYou've already chosen the best response.0@hartnn i see what he did

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt {xy}=\sqrt{x}\sqrt{y}\) ok ? so, \(\sqrt{63}=\sqrt{9}\sqrt{7}=3 \sqrt{7}\) right ?

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0That does not look like any of my answer choices :(

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1that was just simplification of constant terms.... \(3\sqrt 7 \sqrt 7= 2 \sqrt 7\) simplification of 'x' terms is still remaining. and more important thing is that you understand....so that you can do other problems on your own...

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, do you want me to start over ? or take it from a particular step ?

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Start from the beginning please?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1right, lets see term by term, so 63 is 9 times 7 so, \(\sqrt {63}= \sqrt {9}\sqrt{7}=...?\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Yes. And what do we do with the \[\sqrt{7}\] just leave it where it is?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1i was getting there... you first tell me what will be \(\sqrt 9 \sqrt7 =... ?\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0simplify by dividing both \[\sqrt{7}\] and \[\sqrt{63}\] by 7?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1lets finish 1 term entirely \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{3}\] \[\sqrt{2.6}??\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1since \(\sqrt 9=3\) \(\sqrt {63}=\sqrt 9 \sqrt7 =3 \sqrt 7\) got this ?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359950980241:dw

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359951141309:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1ok, so now you have constant terms as \(3\sqrt 7\sqrt 7\) can you combine this ? by factoring out \(\sqrt 7 \)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=...?\) ok with this ?

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Wait...at the end multiplying \[\sqrt{7}\] by 2?

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1359951264530:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=2 \sqrt 7\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0So now we have part of it completed?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes, now take the terms with 'x'.

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1so, did you get this ? \(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0in front of the \[\sqrt{44x^3}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1there is 2 .. \(2\sqrt {44x^3} = 2\sqrt {4} \sqrt{x^2} \sqrt{11x}=2 \times 2x \sqrt {11x}= 4x \sqrt{11x}\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Okay :) \[4x \sqrt{11x}\]

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1similarly, what will be \(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1\(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=3x\sqrt {11x}\) because \(\sqrt 9=3, \: and \: \sqrt {x^2}=x\)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, I wasn't sure how to break it down. I see what you did now :)

P.nut1996
 3 years ago
Best ResponseYou've already chosen the best response.0\[x \sqrt{11x}+2\sqrt{7}\] :D

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes. thats correct . i hope you got each step.

Andresfon12
 3 years ago
Best ResponseYou've already chosen the best response.0this took a lot time :P
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