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Please help me solve?
I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...
 one year ago
 one year ago
Please help me solve? I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...
 one year ago
 one year ago

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P.nut1996Best ResponseYou've already chosen the best response.0
\[2\sqrt{44x ^{3}}\sqrt{7}\sqrt{99x ^{3}}+\sqrt{63}\]
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Combine like terms, right? I don't see how to combine \[2\sqrt{44x ^{3}}\] and \[\sqrt{99x ^{3}}\]
 one year ago

javawarriorBest ResponseYou've already chosen the best response.0
before combining see if you can simplify each term first
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Oh! like 11 goes into both 44 and 99??
 one year ago

javawarriorBest ResponseYou've already chosen the best response.0
see if u can get rid of the roots!
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
How would I go about doing that? Right now I have \[2\sqrt{4x ^{3}}\sqrt{7}\sqrt{9x ^{3}}+\sqrt{63}\]
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Does it look right? Going in the right direction maybe?
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Oh, and I eliminated 7. and the sqrt of 63 is now the sqrt of 9
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\sqrt {63} = \sqrt {9} \sqrt {7}=...?\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Now it looks like \[2\sqrt{4x ^{3}}\sqrt{9x ^{3}}+\sqrt{9}\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...?\) you just can't eliminate 7...
 one year ago

Andresfon12Best ResponseYou've already chosen the best response.0
something is missing
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...? \\\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
But & goes into 7 one time and it goes into 63 9 times. Simplifying... Right?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, \(\sqrt {63}\sqrt 7 = \sqrt{9}\sqrt{7}\sqrt{7} = \sqrt{7}[31]=..?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
you see what i did there ^ ?
 one year ago

Andresfon12Best ResponseYou've already chosen the best response.0
@hartnn i see what he did
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\sqrt {xy}=\sqrt{x}\sqrt{y}\) ok ? so, \(\sqrt{63}=\sqrt{9}\sqrt{7}=3 \sqrt{7}\) right ?
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
That does not look like any of my answer choices :(
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
that was just simplification of constant terms.... \(3\sqrt 7 \sqrt 7= 2 \sqrt 7\) simplification of 'x' terms is still remaining. and more important thing is that you understand....so that you can do other problems on your own...
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, do you want me to start over ? or take it from a particular step ?
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Start from the beginning please?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
right, lets see term by term, so 63 is 9 times 7 so, \(\sqrt {63}= \sqrt {9}\sqrt{7}=...?\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Yes. And what do we do with the \[\sqrt{7}\] just leave it where it is?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
i was getting there... you first tell me what will be \(\sqrt 9 \sqrt7 =... ?\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
simplify by dividing both \[\sqrt{7}\] and \[\sqrt{63}\] by 7?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
lets finish 1 term entirely \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
\[\sqrt{3}\] \[\sqrt{2.6}??\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
since \(\sqrt 9=3\) \(\sqrt {63}=\sqrt 9 \sqrt7 =3 \sqrt 7\) got this ?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
dw:1359950980241:dw
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
dw:1359951141309:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
ok, so now you have constant terms as \(3\sqrt 7\sqrt 7\) can you combine this ? by factoring out \(\sqrt 7 \)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=...?\) ok with this ?
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Wait...at the end multiplying \[\sqrt{7}\] by 2?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
dw:1359951264530:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=2 \sqrt 7\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
So now we have part of it completed?
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes, now take the terms with 'x'.
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
so, did you get this ? \(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
in front of the \[\sqrt{44x^3}\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
there is 2 .. \(2\sqrt {44x^3} = 2\sqrt {4} \sqrt{x^2} \sqrt{11x}=2 \times 2x \sqrt {11x}= 4x \sqrt{11x}\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Okay :) \[4x \sqrt{11x}\]
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
similarly, what will be \(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
\(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=3x\sqrt {11x}\) because \(\sqrt 9=3, \: and \: \sqrt {x^2}=x\)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
Oh, I wasn't sure how to break it down. I see what you did now :)
 one year ago

P.nut1996Best ResponseYou've already chosen the best response.0
\[x \sqrt{11x}+2\sqrt{7}\] :D
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes. thats correct . i hope you got each step.
 one year ago

Andresfon12Best ResponseYou've already chosen the best response.0
this took a lot time :P
 one year ago
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