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 one year ago
Please help me solve?
I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...
 one year ago
Please help me solve? I'm looking at this problem and not seeing how to work it so that my answer comes out looking like the choices...

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P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0\[2\sqrt{44x ^{3}}\sqrt{7}\sqrt{99x ^{3}}+\sqrt{63}\]

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Combine like terms, right? I don't see how to combine \[2\sqrt{44x ^{3}}\] and \[\sqrt{99x ^{3}}\]

javawarrior
 one year ago
Best ResponseYou've already chosen the best response.0before combining see if you can simplify each term first

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Oh! like 11 goes into both 44 and 99??

javawarrior
 one year ago
Best ResponseYou've already chosen the best response.0see if u can get rid of the roots!

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0How would I go about doing that? Right now I have \[2\sqrt{4x ^{3}}\sqrt{7}\sqrt{9x ^{3}}+\sqrt{63}\]

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Does it look right? Going in the right direction maybe?

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Oh, and I eliminated 7. and the sqrt of 63 is now the sqrt of 9

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt {63} = \sqrt {9} \sqrt {7}=...?\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Now it looks like \[2\sqrt{4x ^{3}}\sqrt{9x ^{3}}+\sqrt{9}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...?\) you just can't eliminate 7...

Andresfon12
 one year ago
Best ResponseYou've already chosen the best response.0something is missing

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}=...? \\\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0But & goes into 7 one time and it goes into 63 9 times. Simplifying... Right?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, \(\sqrt {63}\sqrt 7 = \sqrt{9}\sqrt{7}\sqrt{7} = \sqrt{7}[31]=..?\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1you see what i did there ^ ?

Andresfon12
 one year ago
Best ResponseYou've already chosen the best response.0@hartnn i see what he did

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt {xy}=\sqrt{x}\sqrt{y}\) ok ? so, \(\sqrt{63}=\sqrt{9}\sqrt{7}=3 \sqrt{7}\) right ?

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0That does not look like any of my answer choices :(

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1that was just simplification of constant terms.... \(3\sqrt 7 \sqrt 7= 2 \sqrt 7\) simplification of 'x' terms is still remaining. and more important thing is that you understand....so that you can do other problems on your own...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, do you want me to start over ? or take it from a particular step ?

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Start from the beginning please?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1right, lets see term by term, so 63 is 9 times 7 so, \(\sqrt {63}= \sqrt {9}\sqrt{7}=...?\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Yes. And what do we do with the \[\sqrt{7}\] just leave it where it is?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1i was getting there... you first tell me what will be \(\sqrt 9 \sqrt7 =... ?\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0simplify by dividing both \[\sqrt{7}\] and \[\sqrt{63}\] by 7?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1lets finish 1 term entirely \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, \(\sqrt {63}=\sqrt 9 \sqrt7 =... ?\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{3}\] \[\sqrt{2.6}??\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1since \(\sqrt 9=3\) \(\sqrt {63}=\sqrt 9 \sqrt7 =3 \sqrt 7\) got this ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359950980241:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359951141309:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1ok, so now you have constant terms as \(3\sqrt 7\sqrt 7\) can you combine this ? by factoring out \(\sqrt 7 \)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=...?\) ok with this ?

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Wait...at the end multiplying \[\sqrt{7}\] by 2?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359951264530:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(3\sqrt 7\sqrt 7 = \sqrt 7 [31]=2 \sqrt 7\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0So now we have part of it completed?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes, now take the terms with 'x'.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1so, did you get this ? \(\sqrt {44x^3} = \sqrt {4} \sqrt{x^2} \sqrt{11x}\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0in front of the \[\sqrt{44x^3}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1there is 2 .. \(2\sqrt {44x^3} = 2\sqrt {4} \sqrt{x^2} \sqrt{11x}=2 \times 2x \sqrt {11x}= 4x \sqrt{11x}\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Okay :) \[4x \sqrt{11x}\]

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1similarly, what will be \(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=...?\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1\(\sqrt {99x^3} = \sqrt {9} \sqrt{x^2} \sqrt{11x}=3x\sqrt {11x}\) because \(\sqrt 9=3, \: and \: \sqrt {x^2}=x\)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I wasn't sure how to break it down. I see what you did now :)

P.nut1996
 one year ago
Best ResponseYou've already chosen the best response.0\[x \sqrt{11x}+2\sqrt{7}\] :D

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1yes. thats correct . i hope you got each step.

Andresfon12
 one year ago
Best ResponseYou've already chosen the best response.0this took a lot time :P
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