## lily43 2 years ago What is the equation of the lne that passes through points (5,4) and (-2,0)?

1. akhaliq99

rise/run

2. akhaliq99

first find slope

3. akhaliq99

then use y=mx+b

4. akhaliq99

subsitute slope

5. akhaliq99

and then find y intercept

6. mathstudent55

Call point (5, 4) = (x1, y1), and call point (-2, 0) = (x2, y2) Slope = m = (y2 - y1)/(x2 - x1) The equation of the line is: y - y1 = m(x - x1)

7. akhaliq99

he has point slope form

8. akhaliq99

both can be used though

9. lily43

ok. thank u. :)

10. lily43

can u check if im doing it right because i feel like i messed up somewhere?

11. mathstudent55

Sure. Show what you did.

12. lily43

i found the slope using m= Y2-Y1/X2-X1. i got 4/7

13. mathstudent55

Correct, m = 4/7

14. lily43

then i plugged it in y=mx+b. so now i have y=4/7x+b.

15. lily43

i plugged in point (5,4) sonow i have 4=4/7x5+b

16. lily43

then i got 4=20/7+b.thats were im not sure if im right.

17. mathstudent55

|dw:1359950617065:dw| Correct

18. lily43

so if i keep solving it the equation would be y=4/7x+1 1/7

19. mathstudent55

|dw:1359950765775:dw|

20. mathstudent55

|dw:1359950864531:dw|

21. lily43

i got 8/7 to but turned it into 1 and 1/7

22. mathstudent55

You can leave it as 8/7. Your solution is also correct, but it's not usually left with a mixed numeral.

23. lily43

ok. thank u