lily43
What is the equation of the lne that passes through points (5,4) and (2,0)?



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akhaliq99
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rise/run

akhaliq99
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first find slope

akhaliq99
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then use y=mx+b

akhaliq99
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subsitute slope

akhaliq99
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and then find y intercept

mathstudent55
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Call point (5, 4) = (x1, y1), and call point (2, 0) = (x2, y2)
Slope = m = (y2  y1)/(x2  x1)
The equation of the line is:
y  y1 = m(x  x1)

akhaliq99
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he has point slope form

akhaliq99
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both can be used though

lily43
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ok. thank u. :)

lily43
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can u check if im doing it right because i feel like i messed up somewhere?

mathstudent55
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Sure. Show what you did.

lily43
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i found the slope using m= Y2Y1/X2X1. i got 4/7

mathstudent55
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Correct, m = 4/7

lily43
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then i plugged it in y=mx+b.
so now i have y=4/7x+b.

lily43
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i plugged in point (5,4) sonow i have 4=4/7x5+b

lily43
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then i got 4=20/7+b.thats were im not sure if im right.

mathstudent55
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dw:1359950617065:dw
Correct

lily43
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so if i keep solving it the equation would be y=4/7x+1 1/7

mathstudent55
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dw:1359950765775:dw

mathstudent55
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dw:1359950864531:dw

lily43
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i got 8/7 to but turned it into 1 and 1/7

mathstudent55
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You can leave it as 8/7. Your solution is also correct, but it's not usually left with a mixed numeral.

lily43
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ok. thank u