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lily43

  • 3 years ago

What is the equation of the lne that passes through points (5,4) and (-2,0)?

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  1. akhaliq99
    • 3 years ago
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    rise/run

  2. akhaliq99
    • 3 years ago
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    first find slope

  3. akhaliq99
    • 3 years ago
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    then use y=mx+b

  4. akhaliq99
    • 3 years ago
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    subsitute slope

  5. akhaliq99
    • 3 years ago
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    and then find y intercept

  6. mathstudent55
    • 3 years ago
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    Call point (5, 4) = (x1, y1), and call point (-2, 0) = (x2, y2) Slope = m = (y2 - y1)/(x2 - x1) The equation of the line is: y - y1 = m(x - x1)

  7. akhaliq99
    • 3 years ago
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    he has point slope form

  8. akhaliq99
    • 3 years ago
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    both can be used though

  9. lily43
    • 3 years ago
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    ok. thank u. :)

  10. lily43
    • 3 years ago
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    can u check if im doing it right because i feel like i messed up somewhere?

  11. mathstudent55
    • 3 years ago
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    Sure. Show what you did.

  12. lily43
    • 3 years ago
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    i found the slope using m= Y2-Y1/X2-X1. i got 4/7

  13. mathstudent55
    • 3 years ago
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    Correct, m = 4/7

  14. lily43
    • 3 years ago
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    then i plugged it in y=mx+b. so now i have y=4/7x+b.

  15. lily43
    • 3 years ago
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    i plugged in point (5,4) sonow i have 4=4/7x5+b

  16. lily43
    • 3 years ago
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    then i got 4=20/7+b.thats were im not sure if im right.

  17. mathstudent55
    • 3 years ago
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    |dw:1359950617065:dw| Correct

  18. lily43
    • 3 years ago
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    so if i keep solving it the equation would be y=4/7x+1 1/7

  19. mathstudent55
    • 3 years ago
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    |dw:1359950765775:dw|

  20. mathstudent55
    • 3 years ago
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    |dw:1359950864531:dw|

  21. lily43
    • 3 years ago
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    i got 8/7 to but turned it into 1 and 1/7

  22. mathstudent55
    • 3 years ago
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    You can leave it as 8/7. Your solution is also correct, but it's not usually left with a mixed numeral.

  23. lily43
    • 3 years ago
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    ok. thank u

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