anonymous
  • anonymous
use the unit circle to find the value of the trigonmetric function. csc pi/3
Mathematics
katieb
  • katieb
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UnkleRhaukus
  • UnkleRhaukus
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UnkleRhaukus
  • UnkleRhaukus
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UnkleRhaukus
  • UnkleRhaukus
because we are using a Unit circle, ie a circle with radius one, the hypotenuse of the triangle is 1

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UnkleRhaukus
  • UnkleRhaukus
the angle theta is π/3
anonymous
  • anonymous
sorry i still dont get it
anonymous
  • anonymous
is the answer 1/ sin(pi/3)=squareroot of 3
UnkleRhaukus
  • UnkleRhaukus
ops **\[\csc(\theta)=\frac1{\sin(\theta)}=\frac{1}{\text{opposite/hypotenuse}}=\frac{\text{hypotenuse}}{\text{opposite}}\]
anonymous
  • anonymous
thats what i did from my book :(
UnkleRhaukus
  • UnkleRhaukus
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anonymous
  • anonymous
since \[\Large \csc(\theta) =\frac {hyp}{opp}=\frac{1}{\sin(\theta)}\] for \[\frac{\pi}{3}\] since it is unit circle hyp =1 x=1/2 and \[y=opp=\frac{\sqrt{3}}{2}\] so \[\[\Large \csc({\frac{\pi}{3}})=\frac{1}{\frac{\sqrt{3}}{2}}\] \[\Large \csc \frac{\pi}{3}=\frac{2}{\sqrt{3}}\]
anonymous
  • anonymous
i get it now thank u so much : )
anonymous
  • anonymous
you welcome :)
anonymous
  • anonymous
can u tell if this one is right cos pi/3 =square root of 3
anonymous
  • anonymous
no cos is cos=adj/hyp here adj=x=1/2 and hyp=1 cos(pi/3)=1/2
anonymous
  • anonymous
ok thanks

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