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huneya

  • 3 years ago

use the unit circle to find the value of the trigonmetric function. csc pi/3

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  1. UnkleRhaukus
    • 3 years ago
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    |dw:1359955462052:dw|

  2. UnkleRhaukus
    • 3 years ago
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    |dw:1359955677697:dw|

  3. UnkleRhaukus
    • 3 years ago
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    because we are using a Unit circle, ie a circle with radius one, the hypotenuse of the triangle is 1

  4. UnkleRhaukus
    • 3 years ago
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    the angle theta is π/3

  5. huneya
    • 3 years ago
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    sorry i still dont get it

  6. huneya
    • 3 years ago
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    is the answer 1/ sin(pi/3)=squareroot of 3

  7. UnkleRhaukus
    • 3 years ago
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    ops **\[\csc(\theta)=\frac1{\sin(\theta)}=\frac{1}{\text{opposite/hypotenuse}}=\frac{\text{hypotenuse}}{\text{opposite}}\]

  8. huneya
    • 3 years ago
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    thats what i did from my book :(

  9. UnkleRhaukus
    • 3 years ago
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    |dw:1359956217623:dw|

  10. sami-21
    • 3 years ago
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    since \[\Large \csc(\theta) =\frac {hyp}{opp}=\frac{1}{\sin(\theta)}\] for \[\frac{\pi}{3}\] since it is unit circle hyp =1 x=1/2 and \[y=opp=\frac{\sqrt{3}}{2}\] so \[\[\Large \csc({\frac{\pi}{3}})=\frac{1}{\frac{\sqrt{3}}{2}}\] \[\Large \csc \frac{\pi}{3}=\frac{2}{\sqrt{3}}\]

  11. huneya
    • 3 years ago
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    i get it now thank u so much : )

  12. sami-21
    • 3 years ago
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    you welcome :)

  13. huneya
    • 3 years ago
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    can u tell if this one is right cos pi/3 =square root of 3

  14. sami-21
    • 3 years ago
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    no cos is cos=adj/hyp here adj=x=1/2 and hyp=1 cos(pi/3)=1/2

  15. huneya
    • 3 years ago
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    ok thanks

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