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UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359955462052:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359955677697:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1because we are using a Unit circle, ie a circle with radius one, the hypotenuse of the triangle is 1

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1the angle theta is π/3

huneya
 one year ago
Best ResponseYou've already chosen the best response.0sorry i still dont get it

huneya
 one year ago
Best ResponseYou've already chosen the best response.0is the answer 1/ sin(pi/3)=squareroot of 3

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1ops **\[\csc(\theta)=\frac1{\sin(\theta)}=\frac{1}{\text{opposite/hypotenuse}}=\frac{\text{hypotenuse}}{\text{opposite}}\]

huneya
 one year ago
Best ResponseYou've already chosen the best response.0thats what i did from my book :(

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359956217623:dw

sami21
 one year ago
Best ResponseYou've already chosen the best response.2since \[\Large \csc(\theta) =\frac {hyp}{opp}=\frac{1}{\sin(\theta)}\] for \[\frac{\pi}{3}\] since it is unit circle hyp =1 x=1/2 and \[y=opp=\frac{\sqrt{3}}{2}\] so \[\[\Large \csc({\frac{\pi}{3}})=\frac{1}{\frac{\sqrt{3}}{2}}\] \[\Large \csc \frac{\pi}{3}=\frac{2}{\sqrt{3}}\]

huneya
 one year ago
Best ResponseYou've already chosen the best response.0i get it now thank u so much : )

huneya
 one year ago
Best ResponseYou've already chosen the best response.0can u tell if this one is right cos pi/3 =square root of 3

sami21
 one year ago
Best ResponseYou've already chosen the best response.2no cos is cos=adj/hyp here adj=x=1/2 and hyp=1 cos(pi/3)=1/2
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