huneya
use the unit circle to find the value of the trigonmetric function. csc pi/3
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UnkleRhaukus
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UnkleRhaukus
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UnkleRhaukus
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because we are using a Unit circle, ie a circle with radius one, the hypotenuse of the triangle is 1
UnkleRhaukus
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the angle theta is π/3
huneya
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sorry i still dont get it
huneya
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is the answer 1/ sin(pi/3)=squareroot of 3
UnkleRhaukus
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ops **\[\csc(\theta)=\frac1{\sin(\theta)}=\frac{1}{\text{opposite/hypotenuse}}=\frac{\text{hypotenuse}}{\text{opposite}}\]
huneya
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thats what i did from my book :(
UnkleRhaukus
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sami-21
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since
\[\Large \csc(\theta) =\frac {hyp}{opp}=\frac{1}{\sin(\theta)}\]
for \[\frac{\pi}{3}\] since it is unit circle hyp =1 x=1/2 and \[y=opp=\frac{\sqrt{3}}{2}\]
so
\[\[\Large \csc({\frac{\pi}{3}})=\frac{1}{\frac{\sqrt{3}}{2}}\]
\[\Large \csc \frac{\pi}{3}=\frac{2}{\sqrt{3}}\]
huneya
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i get it now thank u so much : )
sami-21
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you welcome :)
huneya
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can u tell if this one is right
cos pi/3 =square root of 3
sami-21
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no
cos is
cos=adj/hyp
here adj=x=1/2 and hyp=1
cos(pi/3)=1/2
huneya
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ok thanks