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huneya

use the unit circle to find the value of the trigonmetric function. csc pi/3

  • one year ago
  • one year ago

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  1. UnkleRhaukus
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    |dw:1359955462052:dw|

    • one year ago
  2. UnkleRhaukus
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    |dw:1359955677697:dw|

    • one year ago
  3. UnkleRhaukus
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    because we are using a Unit circle, ie a circle with radius one, the hypotenuse of the triangle is 1

    • one year ago
  4. UnkleRhaukus
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    the angle theta is π/3

    • one year ago
  5. huneya
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    sorry i still dont get it

    • one year ago
  6. huneya
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    is the answer 1/ sin(pi/3)=squareroot of 3

    • one year ago
  7. UnkleRhaukus
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    ops **\[\csc(\theta)=\frac1{\sin(\theta)}=\frac{1}{\text{opposite/hypotenuse}}=\frac{\text{hypotenuse}}{\text{opposite}}\]

    • one year ago
  8. huneya
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    thats what i did from my book :(

    • one year ago
  9. UnkleRhaukus
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    |dw:1359956217623:dw|

    • one year ago
  10. sami-21
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    since \[\Large \csc(\theta) =\frac {hyp}{opp}=\frac{1}{\sin(\theta)}\] for \[\frac{\pi}{3}\] since it is unit circle hyp =1 x=1/2 and \[y=opp=\frac{\sqrt{3}}{2}\] so \[\[\Large \csc({\frac{\pi}{3}})=\frac{1}{\frac{\sqrt{3}}{2}}\] \[\Large \csc \frac{\pi}{3}=\frac{2}{\sqrt{3}}\]

    • one year ago
  11. huneya
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    i get it now thank u so much : )

    • one year ago
  12. sami-21
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    you welcome :)

    • one year ago
  13. huneya
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    can u tell if this one is right cos pi/3 =square root of 3

    • one year ago
  14. sami-21
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    no cos is cos=adj/hyp here adj=x=1/2 and hyp=1 cos(pi/3)=1/2

    • one year ago
  15. huneya
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    ok thanks

    • one year ago
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