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answer what?
wouldn't that simply equal 8x? if you used the reciprocal?

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Can you show me how you got that?
\[\large \frac{x}{3}=\frac{8}{y}\]Multiply both sides by y,\[\large y\frac{x}{3}=\frac{8}{\cancel y}\cancel y\]The y's on the right will cancel out, giving us,\[\large \frac{xy}{3}=8\]Divide both sides by x,\[\large \frac{\cancel xy}{\cancel x3}=\frac{8}{x}\]Leaving us with,\[\large \frac{y}{3}=\frac{8}{x}\] We basically just traded places with the y and x :) Lemme know if any of that was too confusing.

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