Let Q = (0,4) and R= (12,8) be given points in the plane. We want to find the point P=(x,0) on the x-axis such that the sum of distances PQ+PR is as small as possible. (Before proceeding with this problem, draw a picture!)
To solve this problem, we need to minimize the following function of x:
f(x)=
over the closed interval [a,b] where a= and b=.
We find that f(x) has only one critical point in the interval at x=
where f(x) has value
Since this is smaller than the values of f(x) at the two endpoints, we conclude that this is the minimal sum of distances.

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have you tried this ?
do you know distance formula to get PQ and PR ?

YOU'RE NOT EVEN GOKU HOW DARE YOU USE HIS PICTURE HE WAS MY ONLY FRIEND AS A CHILD

Who is Goku...

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