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sat_chen Group TitleBest ResponseYou've already chosen the best response.0
hold on i didnt know you couldnt post pic from iphone jsut 1 sec
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
draw your question, maybe...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
i have done a lot of the steps so just 1 sec
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
but heres the question dw:1359962006954:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
that will be pretty exhausting..
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
x^4 (x+3) A/x+B/x^2+C/x^3+D/x^4 +E/(x+3)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
do you see my steps ill try posting another pic
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes, D=1, E=4 are correct.
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
yea i got that far phew but how do i solve for the A B and C after that?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
you'll need to put 3 different values of x say x=1,1,2 then you get 3 equations in A,B, C with 3 unknowns...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
can you show me what you mean i dont get what you mean by that
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
should really have listened in my algebra classes sorry :(
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(Ax^3(x+3)+Bx^2(x+3)+Cx^3(x+3)+(x+3)+4x^4\\ =9x^4+17x^3+3x^28x+3\) put x = 1, to get 1 equation in A,B, C
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
it should be Cx (x+3)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
another method is comparing the coefficients to get 3 equations... yes, typo...it should be Cx(x+3)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
like coefficient of x^4 will be A+4 and no right side, its 9 so, A+4= 9 gives A=5
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think you should proceed with comparing the coefficients..
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
so if you plug in x = 1 you get 4A + 4B+ 4C = 16
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i think comapring the coefficients will give you answer much faster, if you have understood it.
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
sorry internet disconnected agian
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
coefficient of x^3 = 3A+B = 15+B on left on right its 17 so, 15+B = 17 gives B=3
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
forget about substitution...
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
ok so what you are saying is that for A you A + 4 = 9 then for B would you B + 3 =17 then for C would you C + 2 =3
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
where did you get thedw:1359963485018:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
it should be B+3A =17
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
then i also guess i dont get how you got the A + 4 either because my logic was wrong
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1359963578884:dw
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
not getting the dw:1359963731639:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(Ax^3(x+3)+Bx^2(x+3)+Cx(x+3)+(x+3)+4x^4\\ =9x^4+17x^3+3x^28x+3 \\ ~ \\Ax^4+3Ax^3 +Bx^3+3Bx^2+Cx^2+3Cx+x+3+4x^4= \\ =9x^4+17x^3+3x^28x+3\)
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
do you have a formula or something that tells us that or how does that work?
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
\(Ax^3(x+3)+Bx^2(x+3)+Cx(x+3)+(x+3)+4x^4\\ =9x^4+17x^3+3x^28x+3 \\ ~ \\Ax^4+3Ax^3 +Bx^3+3Bx^2+Cx^2+3Cx+x+3+4x^4= \\ =9x^4+17x^3+3x^28x+3 \\ ~ \\ (A+4)x^4+(3A+B)x^3+....=...\)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
comapring the cefficiens on left and right, A+4=9 3A+B=17 did you get this ?
 one year ago

sat_chen Group TitleBest ResponseYou've already chosen the best response.0
its not showing it in nice formatting so im writing it down just 1 sec
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
Ax^3(x+3)+Bx^2(x+3)+Cx(x+3)+(x+3)+4x^4=9x^4+17x^3+3x^2−8x+3 Ax^4+3Ax^3+Bx^3+3Bx^2+Cx^2+3Cx+x+3+4x^4=9x^4+17x^3+3x^2−8x+3 (A+4)x^4+(3A+B)x^3+....=9x^4+17x^3+...
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
i just combined like terms on left..
 one year ago
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