Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

camilasanchez

solve ln x= 1- ln (x+2)

  • one year ago
  • one year ago

  • This Question is Closed
  1. camilasanchez
    Best Response
    You've already chosen the best response.
    Medals 0

    I get : lnx+ ln (x+2) ln(x)(x+2) ln (x^2 + 2x)= 1 e^1 = x^2 +2x ? and i need help from there on

    • one year ago
  2. zepdrix
    Best Response
    You've already chosen the best response.
    Medals 0

    I guess we would have to complete the square on the X's. Take half of the b term, and square it.\[\large x^2+bx\]

    • one year ago
  3. camilasanchez
    Best Response
    You've already chosen the best response.
    Medals 0

    so x^2+2x+1 = e ?

    • one year ago
  4. camilasanchez
    Best Response
    You've already chosen the best response.
    Medals 0

    but i get\[x= \sqrt{e}-1\]

    • one year ago
  5. camilasanchez
    Best Response
    You've already chosen the best response.
    Medals 0

    is that the answer?

    • one year ago
  6. blurbendy
    Best Response
    You've already chosen the best response.
    Medals 2

    log(x) = 1 - log(x + 2) log(x) - 1 + log(x+2) = 0 log(x(x+2)) = 1 x(x+2) = e x^2 + 2x = e x^2 + 2x + 1 = 1 + e (x + 1)^2 = 1 + e x+1 = Sqrt[1 + e] or x + 1 = - Sqrt[1 + e} x = Sqrt[1 + e] - 1 or x + 1 = - Sqrt[1 + e] x = Sqrt[1 + e] - 1 or x = -1 -Sqrt[1 + e] Substitute back into the original equation, only 1 will be right x = Sqrt[1 + e] - 1

    • one year ago
  7. zepdrix
    Best Response
    You've already chosen the best response.
    Medals 0

    Ahhh sorry website froze :( erased all my stuff...

    • one year ago
  8. camilasanchez
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks everyone and that sucks! @zepdrix :/ but thanks either way !

    • one year ago
  9. nitz
    Best Response
    You've already chosen the best response.
    Medals 0

    ln(x)+ln(x+2)=1 ln(x(x+2))=ln(e) x(x+2)=e \[x ^{2}+2x-e=0\] D=4+4e=4(1+e) =>sqrtD=2sqrt(1+e) x1=[-2+2sqrt(1-e)]/2=-1+sqrt(1+e)>0 accepted x2=[-2-2sqrt(1-e)]/2=-1-sqrt(1+e)<0 denied

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.