Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
I get : lnx+ ln (x+2) ln(x)(x+2) ln (x^2 + 2x)= 1 e^1 = x^2 +2x ? and i need help from there on
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
I guess we would have to complete the square on the X's. Take half of the b term, and square it.\[\large x^2+bx\]
 one year ago

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
so x^2+2x+1 = e ?
 one year ago

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
but i get\[x= \sqrt{e}1\]
 one year ago

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
is that the answer?
 one year ago

blurbendy Group TitleBest ResponseYou've already chosen the best response.2
log(x) = 1  log(x + 2) log(x)  1 + log(x+2) = 0 log(x(x+2)) = 1 x(x+2) = e x^2 + 2x = e x^2 + 2x + 1 = 1 + e (x + 1)^2 = 1 + e x+1 = Sqrt[1 + e] or x + 1 =  Sqrt[1 + e} x = Sqrt[1 + e]  1 or x + 1 =  Sqrt[1 + e] x = Sqrt[1 + e]  1 or x = 1 Sqrt[1 + e] Substitute back into the original equation, only 1 will be right x = Sqrt[1 + e]  1
 one year ago

zepdrix Group TitleBest ResponseYou've already chosen the best response.0
Ahhh sorry website froze :( erased all my stuff...
 one year ago

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
thanks everyone and that sucks! @zepdrix :/ but thanks either way !
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
ln(x)+ln(x+2)=1 ln(x(x+2))=ln(e) x(x+2)=e \[x ^{2}+2xe=0\] D=4+4e=4(1+e) =>sqrtD=2sqrt(1+e) x1=[2+2sqrt(1e)]/2=1+sqrt(1+e)>0 accepted x2=[22sqrt(1e)]/2=1sqrt(1+e)<0 denied
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.