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AravindG Group TitleBest ResponseYou've already chosen the best response.0
@camilasanchez where exactly are you stuck in this question?
 one year ago

blurbendy Group TitleBest ResponseYou've already chosen the best response.2
ln x = 1 + ln (x+1) lnx 1  lnx + 1 = 0 combine the logs ln  (x) / (x +1)  1 = 0 ln  (x) / (x +1)  = 1 (x) / (x + 1) = e x = e(x + 1) x = ex + e (1  e)x = e x = (e) / (1 e)
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
ln(x)ln(x+1)=1 ln(x/x+1)=ln(e) (x)/(x+1)=e x=(x+1)e x=xe+e x(1e)=e x=(e)/(e1)
 one year ago

Directrix Group TitleBest ResponseYou've already chosen the best response.0
@nitz Check your penultimate step and the last step, please. I didn't follow how the (1e) became (e1). Thanks.
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
sorry.....its x=xe+e xxe=e x(1e)=e x=e/(1e)
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
just a reminder... don't post direct entire solutions, its against CoC.
 one year ago

camilasanchez Group TitleBest ResponseYou've already chosen the best response.0
thanks !
 one year ago

nitz Group TitleBest ResponseYou've already chosen the best response.0
sorry @hartnn
 one year ago
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