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camilasanchez

  • 3 years ago

solve : ln x = 1 + ln (x+1)

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  1. AravindG
    • 3 years ago
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    @camilasanchez where exactly are you stuck in this question?

  2. blurbendy
    • 3 years ago
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    ln x = 1 + ln (x+1) ln|x| -1 - ln|x + 1| = 0 combine the logs ln | (x) / (x +1) | -1 = 0 ln | (x) / (x +1) | = 1 (x) / (x + 1) = e x = e(x + 1) x = ex + e (1 - e)x = e x = (e) / (1 -e)

  3. nitz
    • 3 years ago
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    ln(x)-ln(x+1)=1 ln(x/x+1)=ln(e) (x)/(x+1)=e x=(x+1)e x=xe+e x(1-e)=e x=(e)/(e-1)

  4. Directrix
    • 3 years ago
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    @nitz Check your penultimate step and the last step, please. I didn't follow how the (1-e) became (e-1). Thanks.

  5. nitz
    • 3 years ago
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    sorry.....its x=xe+e x-xe=e x(1-e)=e x=e/(1-e)

  6. hartnn
    • 3 years ago
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    just a reminder... don't post direct entire solutions, its against CoC.

  7. camilasanchez
    • 3 years ago
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    thanks !

  8. nitz
    • 3 years ago
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    sorry @hartnn

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