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TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1\[ \huge x=2^{\frac{ 1 }{ 3 }} + 4^{\frac{ 1 }{ 3 }}\] Show that \[\huge x ^{3} = 6(1+x)\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1can you please show me all woking out as i tried it and it took up like half a page :P(prob wrong working out)

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0post your working out, ill look at it and spot the error.

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1i worked out the Right hand side is equal to 46

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0have you got a scanner?

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0damn, have you got any way of reproducing the page of working you did so I can look at it?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1yea ok... OH YEA the right hand side isnt equal to 46

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359973881754:dw

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1now i dont think you can do anything with the RHS

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1dw:1359973981397:dw

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1im pretty sure there is a shortcut to do this question?

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0do you get x^3 = 23.08393261?

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1im pretty sure we need to show it using indices

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0lol, i dont even know those. As an answer i get \[\pm 2.847322102\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1well i now completely lost with this quesiton :P

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0you were going the right way.\[x^{3} = 6(1+(2^\frac{ 1 }{ 3 }+4^\frac{ 1 }{ 3 }))\] \[x^{3} = 6(1+(\sqrt[3]{2}+\sqrt[3]{4}))\]\[x^{3} = 6(1+(2.847322102))\]\[x^{3} = 23.08393261\]\[x =\sqrt[3]{23.08393261}\]\[x = \pm2.84732210\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1we are meant to prove that \[x ^{3} = 6(1+x)\] not find x

Jonask
 one year ago
Best ResponseYou've already chosen the best response.2\[x^3+y^3=(x+y)(x^2xy+y^2)\] \[\huge x^3=(2+4)(2^{\frac { 2 }{ 3 }}8^{\frac{ 1 }{ 3 }}+4^{\frac{ 2 }{ 3 }})\]

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0oh blast. lol well then if x^3 = 23.08393261 then substitute given in for x therefore \[(\sqrt[3]{2}+\sqrt[3]{4})^{3}\] what does it equal?

Jonask
 one year ago
Best ResponseYou've already chosen the best response.2we not meant to find x but prove

Razzputin
 one year ago
Best ResponseYou've already chosen the best response.0its basic substitution

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge =6(2^{\frac { 2 }{ 3 }}2+4^{\frac{ 2 }{ 3 }})\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1yea but the original question need to be dw:1359975317046:dw

Jonask
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge x^2=2^{\frac{ 2 }{ 3 }}+2+4^{\frac{ 2 }{ 3 }}\] our expresion \[\huge x^24\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1you lost me there :P

Jonask
 one year ago
Best ResponseYou've already chosen the best response.2oh i found an easier way

Kuoministers
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge (2^{\frac{ 1 }{ 3 }} + 4^{\frac{ 1 }{ 3 }})^{3}\] That is the question...

Kuoministers
 one year ago
Best ResponseYou've already chosen the best response.0a + b)3 = a3 + 3a2b + 3ab2 + b3

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1ha i think your right

Jonask
 one year ago
Best ResponseYou've already chosen the best response.2lets factor 2^1/3\[\huge 2^{\frac{ 1 }{ 3 }}(1+2^{\frac{1}{3}})\] \[\huge 2^{\frac{ 1 }{ 3 }3}(1+2^{\frac{ 1 }{ 3 }})^3\] \[\huge 2(1+3(1)2^{1/3}+3(2^{2/3})+2)\] \[\huge 2(3)(1+2^{1/3}+2^{2/3})\] \[\huge 6(1+x)\]

TeemoTheTerific
 one year ago
Best ResponseYou've already chosen the best response.1ok i worked it out by myself but thanks so much for your help jonask
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