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hi
Can someone help me with a question?
Help much appreciated
 one year ago
 one year ago
hi Can someone help me with a question? Help much appreciated
 one year ago
 one year ago

This Question is Closed

TeemoTheTerificBest ResponseYou've already chosen the best response.1
\[ \huge x=2^{\frac{ 1 }{ 3 }} + 4^{\frac{ 1 }{ 3 }}\] Show that \[\huge x ^{3} = 6(1+x)\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
can you please show me all woking out as i tried it and it took up like half a page :P(prob wrong working out)
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
post your working out, ill look at it and spot the error.
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
i worked out the Right hand side is equal to 46
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
have you got a scanner?
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
damn, have you got any way of reproducing the page of working you did so I can look at it?
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
yea ok... OH YEA the right hand side isnt equal to 46
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
dw:1359973881754:dw
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
now i dont think you can do anything with the RHS
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
dw:1359973981397:dw
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
im pretty sure there is a shortcut to do this question?
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
do you get x^3 = 23.08393261?
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
im pretty sure we need to show it using indices
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
lol, i dont even know those. As an answer i get \[\pm 2.847322102\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
well i now completely lost with this quesiton :P
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
you were going the right way.\[x^{3} = 6(1+(2^\frac{ 1 }{ 3 }+4^\frac{ 1 }{ 3 }))\] \[x^{3} = 6(1+(\sqrt[3]{2}+\sqrt[3]{4}))\]\[x^{3} = 6(1+(2.847322102))\]\[x^{3} = 23.08393261\]\[x =\sqrt[3]{23.08393261}\]\[x = \pm2.84732210\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
we are meant to prove that \[x ^{3} = 6(1+x)\] not find x
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[x^3+y^3=(x+y)(x^2xy+y^2)\] \[\huge x^3=(2+4)(2^{\frac { 2 }{ 3 }}8^{\frac{ 1 }{ 3 }}+4^{\frac{ 2 }{ 3 }})\]
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
oh blast. lol well then if x^3 = 23.08393261 then substitute given in for x therefore \[(\sqrt[3]{2}+\sqrt[3]{4})^{3}\] what does it equal?
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
we not meant to find x but prove
 one year ago

RazzputinBest ResponseYou've already chosen the best response.0
its basic substitution
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
\[\huge =6(2^{\frac { 2 }{ 3 }}2+4^{\frac{ 2 }{ 3 }})\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
yea but the original question need to be dw:1359975317046:dw
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
\[\huge x^2=2^{\frac{ 2 }{ 3 }}+2+4^{\frac{ 2 }{ 3 }}\] our expresion \[\huge x^24\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
you lost me there :P
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
oh i found an easier way
 one year ago

KuoministersBest ResponseYou've already chosen the best response.0
\[\huge (2^{\frac{ 1 }{ 3 }} + 4^{\frac{ 1 }{ 3 }})^{3}\] That is the question...
 one year ago

KuoministersBest ResponseYou've already chosen the best response.0
a + b)3 = a3 + 3a2b + 3ab2 + b3
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
ha i think your right
 one year ago

JonaskBest ResponseYou've already chosen the best response.2
lets factor 2^1/3\[\huge 2^{\frac{ 1 }{ 3 }}(1+2^{\frac{1}{3}})\] \[\huge 2^{\frac{ 1 }{ 3 }3}(1+2^{\frac{ 1 }{ 3 }})^3\] \[\huge 2(1+3(1)2^{1/3}+3(2^{2/3})+2)\] \[\huge 2(3)(1+2^{1/3}+2^{2/3})\] \[\huge 6(1+x)\]
 one year ago

TeemoTheTerificBest ResponseYou've already chosen the best response.1
ok i worked it out by myself but thanks so much for your help jonask
 one year ago
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