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amistre64
 one year ago
Best ResponseYou've already chosen the best response.2there is a general conic equation; something like x^2 + xy + y^2 + ... that i can never recall if its a standard conic (not twisted at an angle) you can recognize certain proerties

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2a parabola only has one square in it a circle will have the same constants for x^2 and y^2, and have a + in the middle an ellipse is like a circle, but it has different constants a hyperbola is like an ellipse, but with a minus sign

Isabel☺
 one year ago
Best ResponseYou've already chosen the best response.0uhmm...kay maybe with some examples? oh, wait thanks! :)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2parabola: y = x^2 + .... circle: x^2 + y^2 = 8 ellipse: 4x^2 + 7y^2 = 15 hyperbola: 3x^2  2y^2 = 29

Isabel☺
 one year ago
Best ResponseYou've already chosen the best response.0so why is y=4x^2 a parabola?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2generally, becasue it has one sqaured term in it

Isabel☺
 one year ago
Best ResponseYou've already chosen the best response.0but (xh)^2 = 4p (yk) is the eq. of a parabola right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1359987041116:dw

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2there is an algebra definition and a geometric definition; you presented the geometric one

Isabel☺
 one year ago
Best ResponseYou've already chosen the best response.0what's the difference between those definition ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2one is defined by geometric properties, while te other is defined by arithmetical properties. The two are equivalent, but its just the perspective studies that generated them.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2directrix distance (directrix is a geometric property) v v (xh)^2 = 4p (yk) ^ ^ ^ ^ center x center y

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2y = 4 x^2 x^2 = 4  y (x  0)^2 = 4/4 (y  4) p = 1/4; and center (or vertex in this case) is at (0,4)

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2cost accting exam starting soon, good luck ;)
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