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amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2there is a general conic equation; something like x^2 + xy + y^2 + ... that i can never recall if its a standard conic (not twisted at an angle) you can recognize certain proerties

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2a parabola only has one square in it a circle will have the same constants for x^2 and y^2, and have a + in the middle an ellipse is like a circle, but it has different constants a hyperbola is like an ellipse, but with a minus sign

Isabel☺
 2 years ago
Best ResponseYou've already chosen the best response.0uhmm...kay maybe with some examples? oh, wait thanks! :)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2parabola: y = x^2 + .... circle: x^2 + y^2 = 8 ellipse: 4x^2 + 7y^2 = 15 hyperbola: 3x^2  2y^2 = 29

Isabel☺
 2 years ago
Best ResponseYou've already chosen the best response.0so why is y=4x^2 a parabola?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2generally, becasue it has one sqaured term in it

Isabel☺
 2 years ago
Best ResponseYou've already chosen the best response.0but (xh)^2 = 4p (yk) is the eq. of a parabola right?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1359987041116:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2there is an algebra definition and a geometric definition; you presented the geometric one

Isabel☺
 2 years ago
Best ResponseYou've already chosen the best response.0what's the difference between those definition ?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2one is defined by geometric properties, while te other is defined by arithmetical properties. The two are equivalent, but its just the perspective studies that generated them.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2directrix distance (directrix is a geometric property) v v (xh)^2 = 4p (yk) ^ ^ ^ ^ center x center y

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2y = 4 x^2 x^2 = 4  y (x  0)^2 = 4/4 (y  4) p = 1/4; and center (or vertex in this case) is at (0,4)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.2cost accting exam starting soon, good luck ;)
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