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amistre64Best ResponseYou've already chosen the best response.2
there is a general conic equation; something like x^2 + xy + y^2 + ... that i can never recall if its a standard conic (not twisted at an angle) you can recognize certain proerties
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
a parabola only has one square in it a circle will have the same constants for x^2 and y^2, and have a + in the middle an ellipse is like a circle, but it has different constants a hyperbola is like an ellipse, but with a minus sign
 one year ago

Isabel☺Best ResponseYou've already chosen the best response.0
uhmm...kay maybe with some examples? oh, wait thanks! :)
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
parabola: y = x^2 + .... circle: x^2 + y^2 = 8 ellipse: 4x^2 + 7y^2 = 15 hyperbola: 3x^2  2y^2 = 29
 one year ago

Isabel☺Best ResponseYou've already chosen the best response.0
so why is y=4x^2 a parabola?
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
generally, becasue it has one sqaured term in it
 one year ago

Isabel☺Best ResponseYou've already chosen the best response.0
but (xh)^2 = 4p (yk) is the eq. of a parabola right?
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
dw:1359987041116:dw
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
there is an algebra definition and a geometric definition; you presented the geometric one
 one year ago

Isabel☺Best ResponseYou've already chosen the best response.0
what's the difference between those definition ?
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
one is defined by geometric properties, while te other is defined by arithmetical properties. The two are equivalent, but its just the perspective studies that generated them.
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
directrix distance (directrix is a geometric property) v v (xh)^2 = 4p (yk) ^ ^ ^ ^ center x center y
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
y = 4 x^2 x^2 = 4  y (x  0)^2 = 4/4 (y  4) p = 1/4; and center (or vertex in this case) is at (0,4)
 one year ago

amistre64Best ResponseYou've already chosen the best response.2
cost accting exam starting soon, good luck ;)
 one year ago
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