Isabel☺
  • Isabel☺
R is bounded by y=0 & y= 4 - x^2 .
Mathematics
chestercat
  • chestercat
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Isabel☺
  • Isabel☺
suppose it is a parabola: |dw:1359970089368:dw|
Isabel☺
  • Isabel☺
Isabel☺
  • Isabel☺

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Callisto
  • Callisto
What is the question?
Isabel☺
  • Isabel☺
solve the problem using Disk Method of Solution. Solid V is generated by revolving the given below region R about the x-axis. Draw R and make a sketch of V: R is bounded by y=0 & y= 4 - x^2 .
Isabel☺
  • Isabel☺
solve for volume |dw:1359970762069:dw| @Callisto
Callisto
  • Callisto
Disk method: |dw:1359988516003:dw| \[V = \pi \int_a^b r^2 dx = \pi \int_a^by^2dx\] To find a and b, solve the equations y=0 & y= 4 - x^2. (The x values you get will be the value of a and b) \[y=4-x^2\] Can you do it now?
Isabel☺
  • Isabel☺
a=0 b=4?
Isabel☺
  • Isabel☺
can it be like: |dw:1359971017830:dw|
Callisto
  • Callisto
No.... Solve y=0 and y= 4-x^2 => y = 0 = 4-x^2 So, now, you need to solve 4-x^2 =0 to find a and b.
Isabel☺
  • Isabel☺
oh yea right im confused wait...
Callisto
  • Callisto
^That no was for your first question. You can draw r there.. It doesn't matter where you put the r... since the value of r will be represented by the function y.
Callisto
  • Callisto
Can you solve a quadratic question?
Isabel☺
  • Isabel☺
x= -2 and +2?
Callisto
  • Callisto
Yes. So, the integral is \[V = \pi \int_{-2}^{2} y^2 dx=\pi \int_{-2}^{2} (4-x^2)^2 dx\]Can you do it?
Isabel☺
  • Isabel☺
maybe wait...
Isabel☺
  • Isabel☺
32 pi/ 3?
Callisto
  • Callisto
Not quite...
Isabel☺
  • Isabel☺
oh i forgot to square...
Isabel☺
  • Isabel☺
512pi/ 15?
Callisto
  • Callisto
Yup :)
Isabel☺
  • Isabel☺
yey! thank you!! :)
Callisto
  • Callisto
You're welcome :) Hope that you know how to do it now!
Isabel☺
  • Isabel☺
hopefully yes :) thanks again :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.