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Isabel☺

  • 2 years ago

R is bounded by y=0 & y= 4 - x^2 .

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  1. Isabel☺
    • 2 years ago
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    suppose it is a parabola: |dw:1359970089368:dw|

  2. Isabel☺
    • 2 years ago
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    @apoorvk

  3. Isabel☺
    • 2 years ago
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    @Callisto

  4. Callisto
    • 2 years ago
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    What is the question?

  5. Isabel☺
    • 2 years ago
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    solve the problem using Disk Method of Solution. Solid V is generated by revolving the given below region R about the x-axis. Draw R and make a sketch of V: R is bounded by y=0 & y= 4 - x^2 .

  6. Isabel☺
    • 2 years ago
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    solve for volume |dw:1359970762069:dw| @Callisto

  7. Callisto
    • 2 years ago
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    Disk method: |dw:1359988516003:dw| \[V = \pi \int_a^b r^2 dx = \pi \int_a^by^2dx\] To find a and b, solve the equations y=0 & y= 4 - x^2. (The x values you get will be the value of a and b) \[y=4-x^2\] Can you do it now?

  8. Isabel☺
    • 2 years ago
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    a=0 b=4?

  9. Isabel☺
    • 2 years ago
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    can it be like: |dw:1359971017830:dw|

  10. Callisto
    • 2 years ago
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    No.... Solve y=0 and y= 4-x^2 => y = 0 = 4-x^2 So, now, you need to solve 4-x^2 =0 to find a and b.

  11. Isabel☺
    • 2 years ago
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    oh yea right im confused wait...

  12. Callisto
    • 2 years ago
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    ^That no was for your first question. You can draw r there.. It doesn't matter where you put the r... since the value of r will be represented by the function y.

  13. Callisto
    • 2 years ago
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    Can you solve a quadratic question?

  14. Isabel☺
    • 2 years ago
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    x= -2 and +2?

  15. Callisto
    • 2 years ago
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    Yes. So, the integral is \[V = \pi \int_{-2}^{2} y^2 dx=\pi \int_{-2}^{2} (4-x^2)^2 dx\]Can you do it?

  16. Isabel☺
    • 2 years ago
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    maybe wait...

  17. Isabel☺
    • 2 years ago
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    32 pi/ 3?

  18. Callisto
    • 2 years ago
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    Not quite...

  19. Isabel☺
    • 2 years ago
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    oh i forgot to square...

  20. Isabel☺
    • 2 years ago
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    512pi/ 15?

  21. Callisto
    • 2 years ago
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    Yup :)

  22. Isabel☺
    • 2 years ago
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    yey! thank you!! :)

  23. Callisto
    • 2 years ago
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    You're welcome :) Hope that you know how to do it now!

  24. Isabel☺
    • 2 years ago
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    hopefully yes :) thanks again :)

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