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R is bounded by y=0 & y= 4 - x^2 .

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suppose it is a parabola: |dw:1359970089368:dw|

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Other answers:

What is the question?
solve the problem using Disk Method of Solution. Solid V is generated by revolving the given below region R about the x-axis. Draw R and make a sketch of V: R is bounded by y=0 & y= 4 - x^2 .
solve for volume |dw:1359970762069:dw| @Callisto
Disk method: |dw:1359988516003:dw| \[V = \pi \int_a^b r^2 dx = \pi \int_a^by^2dx\] To find a and b, solve the equations y=0 & y= 4 - x^2. (The x values you get will be the value of a and b) \[y=4-x^2\] Can you do it now?
a=0 b=4?
can it be like: |dw:1359971017830:dw|
No.... Solve y=0 and y= 4-x^2 => y = 0 = 4-x^2 So, now, you need to solve 4-x^2 =0 to find a and b.
oh yea right im confused wait...
^That no was for your first question. You can draw r there.. It doesn't matter where you put the r... since the value of r will be represented by the function y.
Can you solve a quadratic question?
x= -2 and +2?
Yes. So, the integral is \[V = \pi \int_{-2}^{2} y^2 dx=\pi \int_{-2}^{2} (4-x^2)^2 dx\]Can you do it?
maybe wait...
32 pi/ 3?
Not quite...
oh i forgot to square...
512pi/ 15?
Yup :)
yey! thank you!! :)
You're welcome :) Hope that you know how to do it now!
hopefully yes :) thanks again :)

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