## mikaa_toxica13 2 years ago Choose the correct simplification of (x5)2. x7 x10 x3 x25

1. andriod09

do you mean \[5x(2)\] or \[5x^2\]?

2. mikaa_toxica13

5x^2 sorry

3. andriod09

its okay. first thing is first, what do you do with the exponets?

4. mikaa_toxica13

multiply... i think

5. andriod09

do you remember pendas?

6. mikaa_toxica13

yes. that applies here ?

7. andriod09

yes \[5x^2\] what's first?

8. mikaa_toxica13

exponent

9. andriod09

okay then, now you have what?

10. mikaa_toxica13

5x

11. andriod09

what equation would you have now?

12. mikaa_toxica13

13. mikaa_toxica13

the equation is actually (5^2)^2

14. andriod09

no you wouldn't. if you have \[5x^2\] and you spit it, you wouldn't have \[x^10\] you would get \[5x^1\] and \[5x^1\] now what would you do with them?

15. mikaa_toxica13

idk now

16. andriod09

okay, when you split up \[5x^2\] you would get \[5x\] and \[5x\] what would you do with the two \[5x\]

17. mikaa_toxica13

divide ? i dont think my lessons covered this

18. andriod09

no. you wouldn't divide. you remember PEMDAS? you have this equation, \[5x(5x)\] what would you do now?

19. mikaa_toxica13

i dont think my lessons covered this

20. mikaa_toxica13

as in IDK

21. andriod09

okay, first when you see something like oh, lets say: 5(2) it means to multiply. so if you have \[5x(5x)\] you would multiply them. and thus you would get:

22. mikaa_toxica13

x^25

23. mikaa_toxica13

x^10 was correct. why did u say otherwise ?

24. andriod09

no its not, the answer would be \[25x\] you wouldn't do it as the exponet

25. andriod09

look: \[5x^2\] \[5x(5x)\] \[25x\] 5 times 5 isn't 10, its 25.