mikaa_toxica13
Choose the correct simplification of (x5)2.
x7
x10
x3
x25
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andriod09
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do you mean \[5x(2)\] or \[5x^2\]?
mikaa_toxica13
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5x^2 sorry
andriod09
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its okay. first thing is first, what do you do with the exponets?
mikaa_toxica13
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multiply... i think
andriod09
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do you remember pendas?
mikaa_toxica13
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yes. that applies here ?
andriod09
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yes
\[5x^2\] what's first?
mikaa_toxica13
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exponent
andriod09
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okay then, now you have what?
mikaa_toxica13
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5x
andriod09
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what equation would you have now?
mikaa_toxica13
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x^10 my bad
mikaa_toxica13
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the equation is actually (5^2)^2
andriod09
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no you wouldn't. if you have \[5x^2\] and you spit it, you wouldn't have \[x^10\] you would get \[5x^1\] and \[5x^1\] now what would you do with them?
mikaa_toxica13
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idk now
andriod09
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okay, when you split up \[5x^2\] you would get \[5x\] and \[5x\] what would you do with the two \[5x\]
mikaa_toxica13
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divide ? i dont think my lessons covered this
andriod09
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no. you wouldn't divide. you remember PEMDAS? you have this equation, \[5x(5x)\] what would you do now?
mikaa_toxica13
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i dont think my lessons covered this
mikaa_toxica13
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as in IDK
andriod09
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okay, first when you see something like oh, lets say: 5(2) it means to multiply. so if you have \[5x(5x)\] you would multiply them. and thus you would get:
mikaa_toxica13
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x^25
mikaa_toxica13
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x^10 was correct. why did u say otherwise ?
andriod09
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no its not, the answer would be \[25x\] you wouldn't do it as the exponet
andriod09
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look: \[5x^2\] \[5x(5x)\] \[25x\] 5 times 5 isn't 10, its 25.