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magenxoxo
Group Title
help!? pleaseeee :)
Simplify (6x2+ 11x – 3) + (2x2– 17x – 4)
8x2+ 6x – 1
8x2– 6x – 7
8x2+ 6x + 1
8x2– 6x + 7
How do you simplify these equations?
 one year ago
 one year ago
magenxoxo Group Title
help!? pleaseeee :) Simplify (6x2+ 11x – 3) + (2x2– 17x – 4) 8x2+ 6x – 1 8x2– 6x – 7 8x2+ 6x + 1 8x2– 6x + 7 How do you simplify these equations?
 one year ago
 one year ago

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timo86m Group TitleBest ResponseYou've already chosen the best response.1
add like terms
 one year ago

raden_zaikaria Group TitleBest ResponseYou've already chosen the best response.0
6x2+ 11x – 3 + 2x2– 17x – 4
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
(6x2+ 11x – 3) + (2x2 – 17x – 4) 8x^2 4x 7
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[6x^2+ 11x – 3 + 2x^2– 17x – 4\]
 one year ago

Brad1996 Group TitleBest ResponseYou've already chosen the best response.1
B I think
 one year ago

Brad1996 Group TitleBest ResponseYou've already chosen the best response.1
Yeah Its B
 one year ago

Brad1996 Group TitleBest ResponseYou've already chosen the best response.1
Setting it up like this makes it alot easier: (6x2+ 11x – 3) (2x2– 17x – 4)
 one year ago

Brad1996 Group TitleBest ResponseYou've already chosen the best response.1
6x2 + 2x2 = 8x2 11x  17x = 6x 3  4 = 7
 one year ago

raden_zaikaria Group TitleBest ResponseYou've already chosen the best response.0
6x2+ 2x2=8x2 and 11x – 17x = 6x and – 3 – 4 = 7
 one year ago

timo86m Group TitleBest ResponseYou've already chosen the best response.1
(6x2+ 11x – 3) + (2x2 – 17x – 4) 8x^2 6x 7 sorry
 one year ago

raden_zaikaria Group TitleBest ResponseYou've already chosen the best response.0
that ansmwer is 8x26x7
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
Thank you! everyone! :) I get it now :)
 one year ago

raden_zaikaria Group TitleBest ResponseYou've already chosen the best response.0
welcome from malaysia hehe
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
Simplify 2x2(4x2+ 9x – 13) 6x4+ 18x3– 26x2 8x4+ 18x3– 26x2 8x2+ 18x – 26 6x2+ 18x – 26
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
would the answer be D? or A...
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
oh........ why?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
\[2x^2(4x^2+ 9x – 13)\] now we are multiplying
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
so \[2x^2\] should multiply each item in the bracket
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
hmm, so C?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
almost there but notice that even the power changes \[2x^2(4x^2)=8x^{4}\]
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
the powers add each other\[x^a(x^b)=x^{a+b}\]
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
oh. ok. I wasnt sure if i was supposed to change the powers as well.
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
Which of the following represents the area of a rectangle whose length is x – 7 and whose width is x + 12? x2+ 5x – 84 x2– 84 x2– 5x – 84 x2– 84x + 5 IS C THE CORRECT ANSWER?
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
so did you get the answer to the previous one
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
Yes I did.
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.0
you shud ask a new question as a new question
 one year ago

Brad1996 Group TitleBest ResponseYou've already chosen the best response.1
I'm not 100% sure on this question :l
 one year ago

magenxoxo Group TitleBest ResponseYou've already chosen the best response.1
I'll close this question and post a new one so i can give u a medal.
 one year ago
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