anonymous
  • anonymous
Can someone please help me out?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I need A and B....
1 Attachment
anonymous
  • anonymous
question?
anonymous
  • anonymous
Sure, whats your prob?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
question is up there^^^
anonymous
  • anonymous
It doesn't show.
anonymous
  • anonymous
It just says "I need a A or B" And "Can someone help me?"
anonymous
  • anonymous
Here
1 Attachment
anonymous
  • anonymous
You need help or asking us to the the problem?
anonymous
  • anonymous
But first you should know the basics
anonymous
  • anonymous
I need to know what A and B are duh
anonymous
  • anonymous
computer capcity is often measured in bits and bytes. A bit is a the SMALLEST unit. It gives you a hint right there
anonymous
  • anonymous
a byte is 23 bits
anonymous
  • anonymous
divided the two problems to get A
anonymous
  • anonymous
I think : 2^20 =2^(10)2 =2^(4)5
anonymous
  • anonymous
B is pretty much the same
anonymous
  • anonymous
it is all about breaking the exponents
anonymous
  • anonymous
Well good luck :)
anonymous
  • anonymous
thanks
anonymous
  • anonymous
NP

Looking for something else?

Not the answer you are looking for? Search for more explanations.