Here's the question you clicked on:
Bri_Love
help please
i replied it just a moment before
yeah i didnt get it so i re posted to get different help
@bookaholic do you know this one
I'm looking it over to see if I can solve it
Roh how did you solve it?
i think we have to break the exponents of 2^20 lets get togather and break the power
is that the answer for a or B?
lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure
niether and to get the number of bits youd multiply that by 2^3 or 8
10^-10 x 1000 100 = 10^3 so 10^-10 x 10^3 add exponents... 10^-7 m
the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2
@PinkPanda what one it that?
A ok do you ahve B yet?
ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076
ok and do you have task 3?
i gonna have to write this one out so hold on
the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3
Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013
ok that last thing you posted^ what one is that for???
what is for B on task 2?
To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).
What?????? Im so confused!!!!
oh wait I see how you did that ok i get it and that is for B?
ok and then which one is for a and b on #3 that you did?
the really big message i did is for task 3 that one has no part a and b its just one q