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Bri_Love

  • one year ago

help please

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  1. Bri_Love
    • one year ago
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    Please help

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  2. Roh
    • one year ago
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    i replied it just a moment before

  3. Bri_Love
    • one year ago
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    yeah i didnt get it so i re posted to get different help

  4. Bri_Love
    • one year ago
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    @bookaholic do you know this one

  5. bookaholic
    • one year ago
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    I'm looking it over to see if I can solve it

  6. Bri_Love
    • one year ago
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    ok

  7. bookaholic
    • one year ago
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    Roh how did you solve it?

  8. Roh
    • one year ago
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    i think we have to break the exponents of 2^20 lets get togather and break the power

  9. bookaholic
    • one year ago
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    2^20=1048576

  10. Bri_Love
    • one year ago
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    is that the answer for a or B?

  11. Roh
    • one year ago
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    lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

  12. bookaholic
    • one year ago
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    niether and to get the number of bits youd multiply that by 2^3 or 8

  13. Bri_Love
    • one year ago
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    Whattt

  14. PinkPanda
    • one year ago
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    10^-10 x 1000 100 = 10^3 so 10^-10 x 10^3 add exponents... 10^-7 m

  15. bookaholic
    • one year ago
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    the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

  16. Bri_Love
    • one year ago
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    @PinkPanda what one it that?

  17. PinkPanda
    • one year ago
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    the first one

  18. Bri_Love
    • one year ago
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    A ok do you ahve B yet?

  19. PinkPanda
    • one year ago
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    ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076

  20. Bri_Love
    • one year ago
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    ok and do you have task 3?

  21. PinkPanda
    • one year ago
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    one sec

  22. Bri_Love
    • one year ago
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    ok

  23. PinkPanda
    • one year ago
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    i gonna have to write this one out so hold on

  24. Roh
    • one year ago
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    the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3

  25. PinkPanda
    • one year ago
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    Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

  26. Bri_Love
    • one year ago
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    ok that last thing you posted^ what one is that for???

  27. Bri_Love
    • one year ago
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    @PinkPanda

  28. PinkPanda
    • one year ago
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    that the third task

  29. Bri_Love
    • one year ago
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    what is for B on task 2?

  30. PinkPanda
    • one year ago
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    To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

  31. Bri_Love
    • one year ago
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    What?????? Im so confused!!!!

  32. Bri_Love
    • one year ago
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    oh wait I see how you did that ok i get it and that is for B?

  33. PinkPanda
    • one year ago
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    yes that is for 2b

  34. Bri_Love
    • one year ago
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    ok and then which one is for a and b on #3 that you did?

  35. PinkPanda
    • one year ago
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    the really big message i did is for task 3 that one has no part a and b its just one q

  36. Bri_Love
    • one year ago
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    oh ok thanks!

  37. PinkPanda
    • one year ago
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    No problem!

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