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Bri_Love

  • 2 years ago

help please

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  1. Bri_Love
    • 2 years ago
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    Please help

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  2. Roh
    • 2 years ago
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    i replied it just a moment before

  3. Bri_Love
    • 2 years ago
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    yeah i didnt get it so i re posted to get different help

  4. Bri_Love
    • 2 years ago
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    @bookaholic do you know this one

  5. bookaholic
    • 2 years ago
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    I'm looking it over to see if I can solve it

  6. Bri_Love
    • 2 years ago
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    ok

  7. bookaholic
    • 2 years ago
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    Roh how did you solve it?

  8. Roh
    • 2 years ago
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    i think we have to break the exponents of 2^20 lets get togather and break the power

  9. bookaholic
    • 2 years ago
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    2^20=1048576

  10. Bri_Love
    • 2 years ago
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    is that the answer for a or B?

  11. Roh
    • 2 years ago
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    lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

  12. bookaholic
    • 2 years ago
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    niether and to get the number of bits youd multiply that by 2^3 or 8

  13. Bri_Love
    • 2 years ago
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    Whattt

  14. PinkPanda
    • 2 years ago
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    10^-10 x 1000 100 = 10^3 so 10^-10 x 10^3 add exponents... 10^-7 m

  15. bookaholic
    • 2 years ago
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    the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

  16. Bri_Love
    • 2 years ago
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    @PinkPanda what one it that?

  17. PinkPanda
    • 2 years ago
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    the first one

  18. Bri_Love
    • 2 years ago
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    A ok do you ahve B yet?

  19. PinkPanda
    • 2 years ago
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    ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076

  20. Bri_Love
    • 2 years ago
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    ok and do you have task 3?

  21. PinkPanda
    • 2 years ago
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    one sec

  22. Bri_Love
    • 2 years ago
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    ok

  23. PinkPanda
    • 2 years ago
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    i gonna have to write this one out so hold on

  24. Roh
    • 2 years ago
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    the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3

  25. PinkPanda
    • 2 years ago
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    Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

  26. Bri_Love
    • 2 years ago
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    ok that last thing you posted^ what one is that for???

  27. Bri_Love
    • 2 years ago
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    @PinkPanda

  28. PinkPanda
    • 2 years ago
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    that the third task

  29. Bri_Love
    • 2 years ago
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    what is for B on task 2?

  30. PinkPanda
    • 2 years ago
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    To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

  31. Bri_Love
    • 2 years ago
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    What?????? Im so confused!!!!

  32. Bri_Love
    • 2 years ago
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    oh wait I see how you did that ok i get it and that is for B?

  33. PinkPanda
    • 2 years ago
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    yes that is for 2b

  34. Bri_Love
    • 2 years ago
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    ok and then which one is for a and b on #3 that you did?

  35. PinkPanda
    • 2 years ago
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    the really big message i did is for task 3 that one has no part a and b its just one q

  36. Bri_Love
    • 2 years ago
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    oh ok thanks!

  37. PinkPanda
    • 2 years ago
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    No problem!

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