help please

- anonymous

help please

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- schrodinger

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- anonymous

Please help

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- anonymous

i replied it just a moment before

- anonymous

yeah i didnt get it so i re posted to get different help

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## More answers

- anonymous

@bookaholic do you know this one

- anonymous

I'm looking it over to see if I can solve it

- anonymous

ok

- anonymous

Roh how did you solve it?

- anonymous

i think we have to break the exponents of 2^20 lets get togather and break the power

- anonymous

2^20=1048576

- anonymous

is that the answer for a or B?

- anonymous

lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

- anonymous

niether and to get the number of bits youd multiply that by 2^3 or 8

- anonymous

Whattt

- anonymous

10^-10 x 1000
100 = 10^3
so
10^-10 x 10^3
add exponents...
10^-7 m

- anonymous

the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

- anonymous

@PinkPanda what one it that?

- anonymous

the first one

- anonymous

A ok do you ahve B yet?

- anonymous

ultraviolet rays is 0.000010 m
0.00000038

- anonymous

ok and do you have task 3?

- anonymous

one sec

- anonymous

ok

- anonymous

i gonna have to write this one out so hold on

- anonymous

the number of MB in Bytes are : 2^16 . 2^4
and i am trying to find out how to make it based on 2^3

- anonymous

Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x.
Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540).
model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x)
Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454)
Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

- anonymous

ok that last thing you posted^ what one is that for???

- anonymous

@PinkPanda

- anonymous

that the third task

- anonymous

what is for B on task 2?

- anonymous

To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb).
to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

- anonymous

What?????? Im so confused!!!!

- anonymous

oh wait I see how you did that ok i get it and that is for B?

- anonymous

yes that is for 2b

- anonymous

ok and then which one is for a and b on #3 that you did?

- anonymous

the really big message i did is for task 3 that one has no part a and b its just one q

- anonymous

oh ok thanks!

- anonymous

No problem!

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