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anonymous
 3 years ago
help please
anonymous
 3 years ago
help please

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i replied it just a moment before

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yeah i didnt get it so i re posted to get different help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@bookaholic do you know this one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I'm looking it over to see if I can solve it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Roh how did you solve it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think we have to break the exponents of 2^20 lets get togather and break the power

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that the answer for a or B?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0niether and to get the number of bits youd multiply that by 2^3 or 8

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010^10 x 1000 100 = 10^3 so 10^10 x 10^3 add exponents... 10^7 m

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@PinkPanda what one it that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0A ok do you ahve B yet?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok and do you have task 3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i gonna have to write this one out so hold on

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok that last thing you posted^ what one is that for???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is for B on task 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What?????? Im so confused!!!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait I see how you did that ok i get it and that is for B?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok and then which one is for a and b on #3 that you did?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the really big message i did is for task 3 that one has no part a and b its just one q
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