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Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
Please help
 one year ago

Roh Group TitleBest ResponseYou've already chosen the best response.0
i replied it just a moment before
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
yeah i didnt get it so i re posted to get different help
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
@bookaholic do you know this one
 one year ago

bookaholic Group TitleBest ResponseYou've already chosen the best response.0
I'm looking it over to see if I can solve it
 one year ago

bookaholic Group TitleBest ResponseYou've already chosen the best response.0
Roh how did you solve it?
 one year ago

Roh Group TitleBest ResponseYou've already chosen the best response.0
i think we have to break the exponents of 2^20 lets get togather and break the power
 one year ago

bookaholic Group TitleBest ResponseYou've already chosen the best response.0
2^20=1048576
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
is that the answer for a or B?
 one year ago

Roh Group TitleBest ResponseYou've already chosen the best response.0
lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure
 one year ago

bookaholic Group TitleBest ResponseYou've already chosen the best response.0
niether and to get the number of bits youd multiply that by 2^3 or 8
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
10^10 x 1000 100 = 10^3 so 10^10 x 10^3 add exponents... 10^7 m
 one year ago

bookaholic Group TitleBest ResponseYou've already chosen the best response.0
the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
@PinkPanda what one it that?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
the first one
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
A ok do you ahve B yet?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
ok and do you have task 3?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
i gonna have to write this one out so hold on
 one year ago

Roh Group TitleBest ResponseYou've already chosen the best response.0
the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
ok that last thing you posted^ what one is that for???
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
@PinkPanda
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
that the third task
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
what is for B on task 2?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
What?????? Im so confused!!!!
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
oh wait I see how you did that ok i get it and that is for B?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
yes that is for 2b
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
ok and then which one is for a and b on #3 that you did?
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
the really big message i did is for task 3 that one has no part a and b its just one q
 one year ago

Bri_Love Group TitleBest ResponseYou've already chosen the best response.0
oh ok thanks!
 one year ago

PinkPanda Group TitleBest ResponseYou've already chosen the best response.1
No problem!
 one year ago
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