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Bri_Love Group Title

help please

  • one year ago
  • one year ago

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  1. Bri_Love Group Title
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    Please help

    • one year ago
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  2. Roh Group Title
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    i replied it just a moment before

    • one year ago
  3. Bri_Love Group Title
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    yeah i didnt get it so i re posted to get different help

    • one year ago
  4. Bri_Love Group Title
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    @bookaholic do you know this one

    • one year ago
  5. bookaholic Group Title
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    I'm looking it over to see if I can solve it

    • one year ago
  6. Bri_Love Group Title
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    ok

    • one year ago
  7. bookaholic Group Title
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    Roh how did you solve it?

    • one year ago
  8. Roh Group Title
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    i think we have to break the exponents of 2^20 lets get togather and break the power

    • one year ago
  9. bookaholic Group Title
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    2^20=1048576

    • one year ago
  10. Bri_Love Group Title
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    is that the answer for a or B?

    • one year ago
  11. Roh Group Title
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    lolz i mean we have to break the power no need of just calculating this because we should figure out how many 2^3 is inside this figure

    • one year ago
  12. bookaholic Group Title
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    niether and to get the number of bits youd multiply that by 2^3 or 8

    • one year ago
  13. Bri_Love Group Title
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    Whattt

    • one year ago
  14. PinkPanda Group Title
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    10^-10 x 1000 100 = 10^3 so 10^-10 x 10^3 add exponents... 10^-7 m

    • one year ago
  15. bookaholic Group Title
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    the number of bits in a megabyte is 8388608 buy Im not sure how to put that as a power of 2

    • one year ago
  16. Bri_Love Group Title
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    @PinkPanda what one it that?

    • one year ago
  17. PinkPanda Group Title
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    the first one

    • one year ago
  18. Bri_Love Group Title
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    A ok do you ahve B yet?

    • one year ago
  19. PinkPanda Group Title
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    ultraviolet rays is 0.000010 m 0.00000038<visible light<0.00000076

    • one year ago
  20. Bri_Love Group Title
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    ok and do you have task 3?

    • one year ago
  21. PinkPanda Group Title
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    one sec

    • one year ago
  22. Bri_Love Group Title
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    ok

    • one year ago
  23. PinkPanda Group Title
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    i gonna have to write this one out so hold on

    • one year ago
  24. Roh Group Title
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    the number of MB in Bytes are : 2^16 . 2^4 and i am trying to find out how to make it based on 2^3

    • one year ago
  25. PinkPanda Group Title
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    Model the population growth of chessvile with an exponential function (y=50,000 x 1.07^x. Use the function from the first step to find the population of chessville in 2011,2012,2013,2014 (53,500: 57,245: 61,252: 65,540). model the population decline of checkersville with an exponential function ( y= 70,000 x .96^x) Use the function from the third step to find the population of checkersville in 2011,2012,2013,2014 (67,200: 64,512: 61,932: 59,454) Compare the result from the second step and the fourth step. Determine when the population of chessville first exceeds that of chessville ( on January 1, 2014 the population of chessville is 65,540 and the population of checkersvile is 59,454. So the population of chessvill will exceed that of checkersville sometime during the year of 2013

    • one year ago
  26. Bri_Love Group Title
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    ok that last thing you posted^ what one is that for???

    • one year ago
  27. Bri_Love Group Title
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    @PinkPanda

    • one year ago
  28. PinkPanda Group Title
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    that the third task

    • one year ago
  29. Bri_Love Group Title
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    what is for B on task 2?

    • one year ago
  30. PinkPanda Group Title
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    To find the number of megabytes in 1 gigabyte, divide the number of bytes in 1 gigabyte by the number of bytes in 1 megabyte (2^30/2^20 = 2^10 mb). to find the number of bits in 1 gigabyte, multiply the number of bytes in 1 gigabyte by the number if bits in 1 byte ( 2^30 x 2^3 = 2^33 bits).

    • one year ago
  31. Bri_Love Group Title
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    What?????? Im so confused!!!!

    • one year ago
  32. Bri_Love Group Title
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    oh wait I see how you did that ok i get it and that is for B?

    • one year ago
  33. PinkPanda Group Title
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    yes that is for 2b

    • one year ago
  34. Bri_Love Group Title
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    ok and then which one is for a and b on #3 that you did?

    • one year ago
  35. PinkPanda Group Title
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    the really big message i did is for task 3 that one has no part a and b its just one q

    • one year ago
  36. Bri_Love Group Title
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    oh ok thanks!

    • one year ago
  37. PinkPanda Group Title
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    No problem!

    • one year ago
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