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Factor the trinomial: 3x2  7x  6
(3x + 2)(x  3)
(3x  2)(x + 3)
(3x  1)(x  6)
(3x + 1)(x  6)
 one year ago
 one year ago
Factor the trinomial: 3x2  7x  6 (3x + 2)(x  3) (3x  2)(x + 3) (3x  1)(x  6) (3x + 1)(x  6)
 one year ago
 one year ago

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EmmaHBest ResponseYou've already chosen the best response.0
please shown steps im really lost:(
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
ok.... here is my method for a quadratic \[ax^2 + bx + c\] multiply a * c in your question its 3 and  6 3*6 = 18 find the factors of  18 that add to 7..... 9, 2 then do this dw:1360006656091:dw
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.0
A similar method is below: In a polynomial ax^2 + bx + c, find the product ac In your case, 3x^2  7x 6, that woud be 3(6) = 18 Now find two factors of ac that add up to the middle coefficint, b In this case, find two factors of 18 that add up to 7 They are 9 and 2, since 9 * 2 = 18 and 9 + 2 = 7 Nowe break up the middle term, bx, into those two parts In this case it's 3x^2  7x  6 = 3x^2  9x + 2x  6 Now factor by parts: Factor a common factor out of the first two terms, and a common factor out of the last two terms: 3x(x  3) + 2(x  3) Now factor out the common factor, (x  3) (x  3)(3x + 2)
 one year ago
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