A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Factor the trinomial: 3x2  7x  6
(3x + 2)(x  3)
(3x  2)(x + 3)
(3x  1)(x  6)
(3x + 1)(x  6)
 one year ago
Factor the trinomial: 3x2  7x  6 (3x + 2)(x  3) (3x  2)(x + 3) (3x  1)(x  6) (3x + 1)(x  6)

This Question is Closed

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0please shown steps im really lost:(

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0ok.... here is my method for a quadratic \[ax^2 + bx + c\] multiply a * c in your question its 3 and  6 3*6 = 18 find the factors of  18 that add to 7..... 9, 2 then do this dw:1360006656091:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0A similar method is below: In a polynomial ax^2 + bx + c, find the product ac In your case, 3x^2  7x 6, that woud be 3(6) = 18 Now find two factors of ac that add up to the middle coefficint, b In this case, find two factors of 18 that add up to 7 They are 9 and 2, since 9 * 2 = 18 and 9 + 2 = 7 Nowe break up the middle term, bx, into those two parts In this case it's 3x^2  7x  6 = 3x^2  9x + 2x  6 Now factor by parts: Factor a common factor out of the first two terms, and a common factor out of the last two terms: 3x(x  3) + 2(x  3) Now factor out the common factor, (x  3) (x  3)(3x + 2)
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.