Find the Vertex: f(x)= -3x^2-7x+6

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Find the Vertex: f(x)= -3x^2-7x+6

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@saifoo.khan helpppp lol
Hey. To find vertex there's a shortcut.
uh huh

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Other answers:

to find the x-cordinate, use this formula: -b/2a
-(-7)/2(-3)
that will give me the vertex ?
Yes. "x-cordinate" of vertex.
Solve it first..
kk hold on :)
Holding.. :)
got 7/6
vertex is (h,k) right? so i believe that is the "h" ?
Perfect. ^
Find k now.
how to find k lol ?
Lol. Use GOogle. Jk.
i got it lmao :))
hold on
Okay. so now use 7/6 to find it. y = -3x^2-7x+6 y = -3(7/6)^2 -7(7/6) + 6 solve.
got decimal :( hate decimal
so the vertex would be : (7/6, -6.24) ?
Should be 121/12
wtf ?
how? :O
-156/25
hey come back here >:o
VERTEX SHOULD BE -7/6. -_-
THE X-CORDINATE.
CALM DOWN !! CAPS WAR XD
ONE NEGATIVE SIGN RUINS EVERYTHING. >_<
so -7/6 because its opposite of 7/6 ?
you suppose to change it everytime ?
how come my teacher didn't change it -_____-
No. we calculated the x-cordinate wrong in the first place.
oh....XD
\[-\frac{b}{2a} \to -\frac{(-7)}{2(-3)}\to \frac{7}{-6} \to -\frac 76\]
ohhhhhhhhh i see now lmao hhahaha :D
omfg...my whole problem is wrong, thanks saif ! lol : XD
+99 medals
;D Thanks.
hmm instead of 121/10 should i just leave it as 10.08 cuz i have to graph this afterward ?
great now i gotta calculate x-int and y-int :| let see......
Sure. Same thing. Depends on in what format your teacher wants
stay there.. lol
Lol. okays.
stuck lol....find x-intercept?
i know let y=0
0=-3x^2-7x+6
-6=-3x^2-7x <-----stuck here..
Use quadratic formula
oh yee
https://www.khanacademy.org/math/algebra/quadratics/quadratic_formula/v/quadratic-formula-1
but the way my teacher did it was to set y=0 and just add and divide stuff on left and right side...which is confusing but i suppose we can use quadratic aswell :)
Your teacher must have used the "completing the square" method. It's hella confusing. It confuses me too. :/
yeah thats what that was, completing the square lol.... ok i got y= 7+- sqrt(-23)/-6 and what's next ?
i dont think u can reduce it down or anything right? and u can't even square root a negative
https://www.khanacademy.org/math/algebra/quadratics/quadratic_formula/v/quadratic-formula-1
No. We can't reduce.
u can't even square root a negative Yes you're very right.
ohh i get it, it's 7+- 23i/-6
Roots are: -14 and 0.
Roots are: -3 and 2/3
what? @_@
was that you on the video? https://www.khanacademy.org/math/algebra/quadratics/quadratic_formula/v/quadratic-formula-1
Haha. Ofcourse not.

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