A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
need help...first time on site:
limit to inifinity of this
n^.5 plus n^(1/3) divided by
n + 2n^(2/3)
book pulled out n to the neg .5
not sure why. Am thinking there is a better way?
Don't you always divide by highest power?
anonymous
 3 years ago
need help...first time on site: limit to inifinity of this n^.5 plus n^(1/3) divided by n + 2n^(2/3) book pulled out n to the neg .5 not sure why. Am thinking there is a better way? Don't you always divide by highest power?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0IMO, if you divide everything by n^(2/3), you get:\[\frac{ n^{\frac{1}{6}} +n^{\frac{1}{3}}}{ n^{\frac{1}{3}}+2 }\]Now, if n goes to infinity, the powers of n in the numerator go to 0, the denominator goes to infinity, so the whole thing goes to 0. So, I think you're right!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360016424558:dw I believe you divide by the lowest power, which is 1/3. so it would be.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360016724321:dw At this point 1 and 2n^(1/3) do not matter.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1360016863153:dw so the n's cancel out, that leaves (1/6)(2/3) which equals 1/2
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.