Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

If A= x 3 y 3 (matrix) determine the values of x and y for which A^2=A

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

did you square it?
like 3^2?
i mean square the matrix

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

i got \[\left[ \begin{array}{ c c } x^2+3y & 3x+9 \\ xy+3y & 3y+9 \end{array} \right]\]
assuming the matrix is \[\left[ \begin{array}{ c c } x & 3 \\ y & 3 \end{array} \right]\]
that means \[3x+9=3\] so \[x=-2\] and also \(y=-2\)
once you square the matrix, how do you determine the x and y values though?
oh nevermind. how'd you get 3x+9=3
you have \[\left[ \begin{array}{ c c } x^2+3y & 3x+9 \\ x^2+3y & 3y+9 \end{array} \right]=\left[ \begin{array}{ c c } x & 3 \\ y& 3 \end{array} \right]\]
assuming my squaring is correct
so that means each entry has to be the same for the matrices to be equal
therefore \(3x+9=3\implies x=-2\) and \(3y+3=3\implies y=-2\) and so the matrix must be \[\left[ \begin{array}{ c c } -2 & 3 \\ -2 & 3 \end{array} \right]\] by substituting back
sorry i meant \(3y+9=3\implies x=-2\)
ohhh okay!
you can check that this is right by squaring and seeing that you get the same matrix back
also you might want to check that i squared the matrix correctly, but i think it is right
gotta run
okay:) So, the steps to a problem like this is to first follow the formula (A^2=A) for the matrix. Then just solve..
when it said A^2=A I first thought it mean like x^2 and 3^2.. i haven't learned this yet lol

Not the answer you are looking for?

Search for more explanations.

Ask your own question