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set y =0, and solve the quadratic equation

\[x ^{2}-8x-1=0\]

Set a=1, b=-8 and c=-1 in the QF.

\[x=4+\sqrt{17} or x=4-\sqrt{17}\]

yup exactly

you need to use the quadratic formula

\[x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }\]

so the final answer would be

\[(4+\sqrt{17}, 0) and (4-\sqrt{17}, 0)\]

8 square root 68 over 8?

yup

is it over 4?

if a =1 yes

so am i right? it is over 4

over 2x1