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monroe17 Group Title

Solve the equation. 2x-3y-5z=-16

  • one year ago
  • one year ago

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  1. Zelda Group Title
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    Impossible. You need a minimum of 3 equations, or two given variables.

    • one year ago
  2. monroe17 Group Title
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    there's more.. I need to find the n-vector form

    • one year ago
  3. monroe17 Group Title
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    x __ __ __ y = __ + __ s + __ t z __ __ __

    • one year ago
  4. monroe17 Group Title
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    @saifoo.khan can you help me please?

    • one year ago
  5. JEdwards85 Group Title
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    2x-3y-5z=-16 x+3y+5z-16/2=1 1/2y+2 1/2z-8 that what my calculator said.

    • one year ago
  6. monroe17 Group Title
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    ^ huh?

    • one year ago
  7. JEdwards85 Group Title
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    I put it to my algebra calculator and that the answer I got.

    • one year ago
  8. monroe17 Group Title
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    I'm pretty sure that's wrong ^. But thanks for trying.

    • one year ago
  9. JEdwards85 Group Title
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    Ok

    • one year ago
  10. mathsmind Group Title
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    has anyone answered your question?

    • one year ago
  11. mathsmind Group Title
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    and if not can you kindly tell me are you solving for x

    • one year ago
  12. monroe17 Group Title
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    nope, someone tried. I can't figure it out to save my life. In my second comment ( up there ) I'm solving for all the "__"

    • one year ago
  13. mathsmind Group Title
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    ok it is simple

    • one year ago
  14. mathsmind Group Title
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    first of all solve for x then for y then for z

    • one year ago
  15. mathsmind Group Title
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    i will show you how

    • one year ago
  16. monroe17 Group Title
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    you can't solve for x,y,z unless you have more equations..

    • one year ago
  17. mathsmind Group Title
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    wait and you will see

    • one year ago
  18. mathsmind Group Title
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    2x-3y-5z=-16

    • one year ago
  19. mathsmind Group Title
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    step one: 2x = 3y + 5z =16

    • one year ago
  20. mathsmind Group Title
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    step two: \[x = \frac{ 3 }{ 2 }y + \frac{ 5 }{2 }z -8\]

    • one year ago
  21. mathsmind Group Title
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    \[x = 1.5y + 2.5z -8\]

    • one year ago
  22. mathsmind Group Title
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    are you following

    • one year ago
  23. monroe17 Group Title
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    yes

    • one year ago
  24. mathsmind Group Title
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    so this is your value of x

    • one year ago
  25. mathsmind Group Title
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    now i will solve for y if you want?

    • one year ago
  26. mathsmind Group Title
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    are you there?

    • one year ago
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