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monroe17

  • 2 years ago

Solve the equation. 2x-3y-5z=-16

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  1. Zelda
    • 2 years ago
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    Impossible. You need a minimum of 3 equations, or two given variables.

  2. monroe17
    • 2 years ago
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    there's more.. I need to find the n-vector form

  3. monroe17
    • 2 years ago
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    x __ __ __ y = __ + __ s + __ t z __ __ __

  4. monroe17
    • 2 years ago
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    @saifoo.khan can you help me please?

  5. JEdwards85
    • 2 years ago
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    2x-3y-5z=-16 x+3y+5z-16/2=1 1/2y+2 1/2z-8 that what my calculator said.

  6. monroe17
    • 2 years ago
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    ^ huh?

  7. JEdwards85
    • 2 years ago
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    I put it to my algebra calculator and that the answer I got.

  8. monroe17
    • 2 years ago
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    I'm pretty sure that's wrong ^. But thanks for trying.

  9. JEdwards85
    • 2 years ago
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    Ok

  10. mathsmind
    • 2 years ago
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    has anyone answered your question?

  11. mathsmind
    • 2 years ago
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    and if not can you kindly tell me are you solving for x

  12. monroe17
    • 2 years ago
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    nope, someone tried. I can't figure it out to save my life. In my second comment ( up there ) I'm solving for all the "__"

  13. mathsmind
    • 2 years ago
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    ok it is simple

  14. mathsmind
    • 2 years ago
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    first of all solve for x then for y then for z

  15. mathsmind
    • 2 years ago
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    i will show you how

  16. monroe17
    • 2 years ago
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    you can't solve for x,y,z unless you have more equations..

  17. mathsmind
    • 2 years ago
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    wait and you will see

  18. mathsmind
    • 2 years ago
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    2x-3y-5z=-16

  19. mathsmind
    • 2 years ago
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    step one: 2x = 3y + 5z =16

  20. mathsmind
    • 2 years ago
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    step two: \[x = \frac{ 3 }{ 2 }y + \frac{ 5 }{2 }z -8\]

  21. mathsmind
    • 2 years ago
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    \[x = 1.5y + 2.5z -8\]

  22. mathsmind
    • 2 years ago
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    are you following

  23. monroe17
    • 2 years ago
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    yes

  24. mathsmind
    • 2 years ago
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    so this is your value of x

  25. mathsmind
    • 2 years ago
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    now i will solve for y if you want?

  26. mathsmind
    • 2 years ago
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    are you there?

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